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brilliants [131]
3 years ago
10

What is the equation of the line that passes through the point (-8,3) and has a slope of -1/4

Mathematics
2 answers:
harina [27]3 years ago
6 0

Answer:

y - 3 = (-1/4)(x + 8)

Step-by-step explanation:

Apply the point-slope form y - k = m(x - h).  Let h = -8, k = 3 and m = -1/4:

y - 3 = (-1/4)(x + 8)  passes through the point (-8,3) and has a slope of -1/4

Nookie1986 [14]3 years ago
4 0
The slope is -1/4, which is -0.25x. We know that we are exactly 8 units to the left of the y axis, so we can use the slope to determine the change within the coordinates as the line moves across the graph. The slope has a rise of -1 and a run of 4, meaning every 4 units to the right will be 1 unit up. We must move 8 units to the right, which in turn moves the graph down 8 quarter units. 8 x (1/4) is 2, so we know that the graph has moved down 2 units. (Down because the graph has a negative slope). (-8,3)->(0,1). From this coordinate, we can see the y intercept is 1. Since y=mx+b, we can write y=-1/4x+1. This is your equation. (Sorry for the length, wanted to be thorough)
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The sum of the circumference of two circles is 38π cm and the sum of their areas is 193π cm². Calculate the radii of the circles
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Answer:

The radii of the circles are 12 cm and 7cm.

Step-by-step explanation:

Let the radii of the circles be r_{1}\ and\ r_{2}

Given:

Sum of circumference of two circles= 38π cm

Formula for circumference of a circle with radius r = 2πr

2\pi r_{1}+2\pi r_{2}=38\pi \\r_{1}+r_{2}=19------------1

Sum of areas of two circles= 193π cm²

Area of circle with radius r = πr²

\pi r_{1}^{2}+\pi r_{2}^{2}=193\pi \\r_{1}^{2}+r_{2}^{2}=193-------2

Substituting r2 = 19 - r1 in equation 2 we get:

r_{1}^{2}+(19-r_{1})^{2}=193\\2r_{1}^{2}-38r_{1}+168=0\\r_{1}^{2}-19r_{1}+84=0\\(r_{1}-12)(r_{1}-7)=0\\r_{1}=12\ or\ 7

Then r2 = 19 - r1

r_{2}=12\ or\ 7

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Step-by-step explanation:

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TiliK225 [7]

Answer:

x = 22, y = -4

Step-by-step explanation:

x + 6y = -2 --- Equation 1

-x = 3y - 10 --- Equation 2

Equation 2 ×(-1): x = -3y + 10 --- Equation 3

Substitute x = -3y + 10 into Equation 1:

x + 6y = -2

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3y = -2-10

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y = -12 ÷ 3

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Substitute y = -4 into Equation 3:

x = -3y + 10

x = -3(-4) + 10

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