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Schach [20]
3 years ago
14

to advertise o radio,the radio station charges 32naira for the first 10 words and 2naira per word for every additional word.how

much will it cost to place an advertisement of 68 words on radio?​
Mathematics
1 answer:
o-na [289]3 years ago
6 0

Answer:

Cost for 68 words = 148 naira

Step-by-step explanation:

Given that:

Cost of first ten words = 32 naira

Cost of additional words = 2 naira per word

Let,

x be the number of additional words.

y be the total cost

y = 2x + 32

We have to find the cost for 68 words.

The cost of first 10 words will be 32 naira.

Additional words = 68 - 10 = 58 words

Putting x = 58 in the equation

y = 2(58) + 32

y = 116 + 32

y = 148

Hence,

Cost for 68 words = 148 naira

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Is the square root of 225 a rational number?
MArishka [77]

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Annabella time for a race was 24.2 seconds. Another runnee's time was 6.43 seconds faster write and evaluate an equation with to
liberstina [14]

Answer:

Step-by-step explanation:

Given Annabella time for a race is 24.2 seconds, if another runnee's time was 6.43 seconds faster, then the time taken for another  runnee's time will be 24.2 - 6.43 = 17.77secs.

Let a variable X be the difference between annabelle's time and the other runners time.

X = annabelle's time  - other runners time.

X = 24.2 - (24.2 - 6.43)

X = 24.2-24.2+6.43

X = 6.43seconds

Hence the expression between annabelle's time and the other runners time is X = 24.2 - (24.2 - 6.43)

<em>The difference between annabelle's time and the other runners time is 6.43seconds</em>

8 0
4 years ago
A land owner is planning to build a fenced-in, rectangular patio behind his garage, using his garage as one of the "walls." He
Vitek1552 [10]

Answer:

Maximum area = 800 square feet.

Step-by-step explanation:

In the figure attached,

Rectangle is showing width = x ft and the side towards garage is not to be fenced.

Length of the fence has been given as 80 ft.

Therefore, length of the fence = Sum of all three sides of the rectangle to be fenced

80 = x + x + y

80 = 2x + y

y = (80 - 2x)

Now area of the rectangle A = xy

Or function that represents the area of the rectangle is,

A(x) = x(80 - 2x)

A(x) = 80x - 2x²

To find the maximum area we will take the derivative of the function with respect to x and equate it to zero.

A'(x)=\frac{d}{dx}(80x-2x^{2})

             = 80 - 4x

A'(x) = 80 - 4x = 0

4x = 80

x = \frac{80}{4}

x = 20

Therefore, for x = 20 ft area of the rectangular patio will be maximum.

A(20) = 80×(20) - 2×(20)²

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Maximum area of the patio is 800 square feet.

7 0
4 years ago
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