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3 years ago

What is the measure of the given angle in degrees? A=pi/3

Mathematics

2 answers:

marissa [1.9K]3 years ago

7 0

A= pi/3 and pi is 180°
So A=180/3 = 60°

melomori [17]3 years ago

5 0

Answer:

A = pi/3 = 1.05°

Step-by-step explanation:

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248 miles per hour = x meters per second. Round to the nearest hundredth.

Alja [10]

Answer:

Step-by-step explanation:

This problem is based on unit conversion from miles per hour to meter per second.'

From tables 1 mph= 0.44704 m/s

Given 248 mph to be converted to meters per second.

hence we have

1 mph= 0.44704 m/s

248 mph= x

cross multiplying we have

x= 110.86592 m/s

to the nearest hundreth we have

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3 years ago

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2 years ago

What properties does a square have in common with a quadrilateral?

satela [25.4K]

B and C are the only correct answers

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3 years ago

Find the slope of the line y=5x+4

Tatiana [17]

Answer:

Slope = 5

Step-by-step explanation:

y = mx + b

m = slope

Slope = 5

6 0

3 years ago

Read 2 more answers

Suppose an unknown radioactive substance produces 8000 counts per minute on a Geiger counter at a certain time, and only 500 cou

mariarad [96]

Answer:

The half-life of the radioactive substance is of 3.25 days.

Step-by-step explanation:

The amount of radioactive substance is proportional to the number of counts per minute:

This means that the amount is given by the following differential equation:

$\frac{dQ}{dt} = -kQ$

In which k is the decay rate.

The solution is:

$Q(t) = Q(0)e^{-kt}$

In which Q(0) is the initial amount:

8000 counts per minute on a Geiger counter at a certain time

This means that $Q(0) = 8000$

500 counts per minute 13 days later.

This means that $Q(13) = 500$ . We use this to find k.

$Q(t) = Q(0)e^{-kt}$

$500 = 8000e^{-13k}$

$e^{-13k} = \frac{500}{8000}$

$\ln{e^{-13k}} = \ln{\frac{500}{8000}}$

$-13k = \ln{\frac{500}{8000}}$

$k = -\frac{\ln{\frac{500}{8000}}}{13}$

$k = 0.2133$

$Q(t) = Q(0)e^{-0.2133t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.2133t}$

$0.5Q(0) = Q(0)e^{-0.2133t}$

$e^{-0.2133t} = 0.5$

$\ln{e^{-0.2133t}} = \ln{0.5}$

$-0.2133t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.2133}$

$t = 3.25$

The half-life of the radioactive substance is of 3.25 days.

7 0

3 years ago