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3 years ago

Identify the domain and range, then evaluate each function for the given value of x.

Mathematics

1 answer:

maria [59]3 years ago

6 0

Answer:

See below

Step-by-step explanation:

Domains are the first values and range are the second values given in the brackets.

Domain = {10, - 2, 5, 3}

Range = {7, 4, 3, 10}

I the third bracket, at x = 5, y is 3.

So,

f(5) = 3

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Graph the line -3x + y = -6

mart [117]

Answer:

Step-by-step explanation:

Step 1: Rearrange -3x + y = -6 into y = mx + b

y = 3x - 6

Step 2: Find the y-intercept

The y-intercept is "b" so in this case the y-intercept is -6

Step 3: Use $\frac{rise}{run}$ to graph this equation

We start at (0,3) the y-intercept and go up by 3 and left by 1 ( $\frac{rise}{run} =\frac{3}{1}$ )

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4 years ago

If sin (7y) = cos (5y + 14), find y.

Reil [10]

Answer:

Step-by-step explanation:

sin(7y)=cos(5y+14)=sin(90-(5y+14))=sin(76-5y)

7y=76-5y

12y=76

y=76/12=19/3

sin(7y)=cos (5y+14)=sin (90+(5y+14))=sin (5y+104)

7y=5y+104

2y=104

y=52

7 0

4 years ago

What is the solution for the equation 5/3b^3-2b^2-5=2/b^3-2

PilotLPTM [1.2K]

I looked it up and it said it was c

7 0

3 years ago

Read 2 more answers

It takes Janelle four hours to drive to New York. If New York is 240 miles from Boston, what is Janelle’s speed per hour?

Lemur [1.5K]

Answer:

60 mph

Step-by-step explanation:

mph=miles/hours

240/4=60

60 miles per hour

3 0

3 years ago

Example 1: Calculation of Normal Probabilities Using ????????-Scores and Tables of Standard Normal Areas The U.S. Department of

Molodets [167]

Answer:

i) 0.872

ii) 0.300

iii) 0.76

iv) 0.704

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $261.50 per month

Standard Deviation, σ = $16.25

We are given that the distribution of monthly food cost for a 14- to 18-year-old male is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(Less than $280)

$P( x < 280) = P( z < \displaystyle\frac{280 - 261.50}{16.25}) = P(z< 1.138)$

Calculation the value from standard normal z table, we have,

$P(x < 280) = 0.872 = 87.2\%$

b) P(More than $270)

P(x > 270)

$P( x > 270) = P( z > \displaystyle\frac{270 - 261.50}{16.25}) = P(z > 0.523)$

$= 1 - P(z \leq 0.523)$

Calculation the value from standard normal z table, we have,

$P(x > 270) = 1 - 0.700 = 0.300 = 30.0\%$

c) P(More than $250)

P(x > 250)

$P( x > 250) = P( z > \displaystyle\frac{250 - 261.50}{16.25}) = P(z > -0.707)$

$= 1 - P(z \leq -0.707)$

Calculation the value from standard normal z table, we have,

$P(x > 250) = 1 - 0.240 = 0.76 = 76.0\%$

d) P(Between $240 and $275)

$P(240 \leq x \leq 275) = P(\displaystyle\frac{240 - 261.50}{16.25} \leq z \leq \displaystyle\frac{275-261.50}{16.25}) = P(-1.323 \leq z \leq 0.8307)\\\\= P(z \leq 0.8307) - P(z < -1.323)\\= 0.797 - 0.093 = 0.704 = 70.4\%$

$P(240 \leq x \leq 275) = 70.4\%$

e) Thus, 0.704 is the probability that the monthly food cost for a randomly selected 14- to 18-year-old male is between $240 and $275.

5 0

3 years ago