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Thepotemich [5.8K]
3 years ago
9

Which of the following points lies on the graph of the function y = 3 Superscript x? a. (1, 0) c. (3, 1) b. (2, 9) d. (0, 3)

Mathematics
2 answers:
Semmy [17]3 years ago
7 0

Answer:

Its b (2,9)

Step-by-step explanation:

I got it on edge

eimsori [14]3 years ago
5 0

Answer:

1, 0

Step-by-step explanation:

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it says it all in the picture I need help, please, and also show reasoning and how you got the answer
Alenkasestr [34]

Answer:

y = -2  when x = 0

Step-by-step explanation:

We are given points on the line such as ( 2, 2) and (6, 10) so we can find the equation of the line then find point (x=0, y=?).

General equation of the line is y = mx +b, where m is the slope and

b is y-intercept (where the line crosses the y-axis)

The slope m = (y2-y1)/ (x2-x1) = (10-2)/(6-2) = 8/4 = 2

Now the equation is y = 2x +b

To find b we substitute any of the points that are on the line, for example

(x=2, y=2) in the equation 2=2*2+b; 2-4 =b; -2 = b

The equation is y=2x -2

If x= 0 then y=2*0 -2; y = -2

4 0
3 years ago
154 is the same as the product of 158 and n, decreased by 132
grandymaker [24]

Answer:

Equation: 154 = 158n - 132 n = 11/6

Step-by-step explanation:

Let's start by converting this into an equation. Some keywords to look for are "is" which means an equal sign (=), "product" which is multiplication (*), and "decreased" which means a minus sign (-):

So this is our equation: 154 = 158n - 132

Now we have to solve for n:

First, we add 132 to both sides to isolate the n more:

286 = 158n

Then to completely isolate the n, we divide both sides by 158

286

------    =     n

156

<u>n = 11/6, final answer.</u>

8 0
2 years ago
Please help me with this it’s due soon
KonstantinChe [14]

Answer:

39.5 degrees

Step-by-step explanation:

180-101=79

79/2=39.5

3 0
3 years ago
Read 2 more answers
What is the slope intercept form of y-2=-5/2(x-2)
Vlad [161]

Answer:

y=-5/2+0

Step-by-step explanation:

add 2 to both side

y-2(+2)=-5/2(x-2(+2))

y=-5/2x+0

3 0
3 years ago
Y equals equation for the line that passes through the points (-6,2) and (1,16)
8_murik_8 [283]

Slope-intercept form:  y = mx + b  

[m is the slope, b is the y-intercept or the y value when x = 0  --->  (0, y)  or the point where the line crosses through the y-axis]

To find the slope, you use the slope formula:

m=\frac{y_2-y_1}{x_2-x_1}       And plug in the two points

(-6, 2)  =  (x₁ , y₁)

(1, 16)  =  (x₂ , y₂)

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{16-2}{1-(-6)}     [two negatives cancel each other out and become positive]

m=\frac{16-2}{1+6}

m=\frac{14}{7}

m = 2       Now that you found m, plug it into the equation

y = mx + b

y = 2x + b        To find b, plug in one of the points into the equation

(-6, 2)

y = 2x + b

2 = 2(-6) + b

2 = -12 + b          Add 12 on both sides

14 = b

(1, 16)

y = 2x + b

16 = 2(1) + b          Subtract 2 on both sides

14 = b        

Now that you found b, plug it into the equation

y = 2x + 14

8 0
3 years ago
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