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Doss [256]
3 years ago
10

− ( x + 3 ) − 2 ( 4 x − 3 ) I need the correct steps

Mathematics
1 answer:
lianna [129]3 years ago
8 0

Answer:

-9x + 3

Step-by-step explanation:

You would distribute first.

− ( x + 3 ) − 2 ( 4x − 3 ) → -x − 3 − 8x + 6

(If you see a negative sign in front of a parenthesis without a number, its usually a negative 1)

From there, you would combine like terms.

-x − 3 − 8x + 6 → -9x + 3

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If you place a 89-foot ladder against the top of a 80-foot building, how many feet will
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Answer:

\large \boxed{\text{39 ft}}

Step-by-step explanation:

Let x be the distance from the foot of the ladder to the base of the building.

We have a right triangle, so we can use Pythagoras' Theorem.

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How do I multiply indices
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Read 2 more answers
For a standardized psychology examination intended for psychology majors, the historical data show that scores have a mean of 50
Volgvan

Answer:

P(\bar X>530)=1-0.808=0.192

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the scores, and for this case we know the distribution for X is given by:

X \sim N(\mu=505,\sigma=170)  

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(505,\frac{170}{\sqrt{35}})

2) Calculate the probability

We want this probability:

P(\bar X>530)=1-P(\bar X

The best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\bar X >530)=1-P(Z

P(\bar X>530)=1-0.808=0.192

3 0
3 years ago
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