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sineoko [7]
2 years ago
9

Which equation represents the line passing through points A and C on the graph below?

Mathematics
1 answer:
romanna [79]2 years ago
5 0
The answer is y= x+1
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Which of the following could be the numbers of left-handed and right-handed students at West Junior
nordsb [41]

Answer:

The anwers Is C and E.

Step-by-step explanation:

A relationship between two quantities is proportional if the ratio between those quantities is always equivalent.

Hint #22 / 4

Let's look at the ratio between right- and left-handed students at East Middle School.

6

0

9

right

5

8

left

=

1

0

.

5

right per left

58left

609right

​  =10.5 right per left

At East Middle School, there are

1

0

.

5

10.5 right-handed students for every left-handed student.

Hint #33 / 4

Now we can compare the other combinations of values for left-handed and right-handed students. Which ratios are equivalent to the ratio at East Middle School?

So the anwers is C AND E

3 0
3 years ago
Can y’all please help
xxMikexx [17]
Given:  f(x) = 2x^2 +5sqrt(x-2)

Evaluate this for x=6:

f(6) = 2(6)^2 + 5sqrt(6-2) = 72 + 5(2) = 72 + 10 = 82 (answer)
4 0
3 years ago
ASAP!! PLEASE I NEED HELP!!
sergey [27]

Answer:

If the length is 50 yd, the width is  60 yd.

If the length is 40 yd, the width is  75 yd.

If the length is 48 yd, the width is  62.5 yd.

If the length is 36 yd, the width is 83.33 yd.

The length and the width vary inversely because when the length decreased the width increased

Step-by-step explanation:

<em>The area of any rectangle A = L × W, where</em>

  • L is its length
  • W is its width

<em>The relation is direct proportion if the quotient of two quantity equals constant  (y/x = k, when y and x increased) and inverse if the product of the two quantity equals constant (yx = k, when x increased y decreased and vice versa)  </em>

∵ The area of the rectangular plot of land = 3000 yards²

∴ A = 3000

∵ Its length = 50 yards

∴ L = 50

→ Substitute them in the rule above to find W

∵ 3000 = 50 × W

→ Divide both sides by 50 to find W

∴ 60 = W

∴ The width of the plot is 60 yards

∵ Its length = 40 yards

∴ L = 40

→ Substitute them in the rule above to find W

∵ 3000 = 40 × W

→ Divide both sides by 40 to find W

∴ 75 = W

∴ The width of the plot is 75 yards

∵ Its length = 48 yards

∴ L = 48

→ Substitute them in the rule above to find W

∵ 3000 = 48 × W

→ Divide both sides by 48 to find W

∴ 62.5 = W

∴ The width of the plot is 62.5 yards

∵ Its length = 36 yards

∴ L = 36

→ Substitute them in the rule above to find W

∵ 3000 = 36 × W

→ Divide both sides by 36 to find W

∴ 83. 33 = W

∴ The width of the plot is  83.33 yards

∵ The area is a constant value

∵ A = LW

→ The product of L and W equals the constant value, can you discover

   that from the values of L and W

∴  The length and the width of the rectangular plot vary inversely

7 0
3 years ago
Planners of an experiment are evaluating the design of a sphere of radius r that is to be filled with helium (0°c, 1 atm pressur
Vikentia [17]
The solution is:A mole of gas occupies 22.4 L A liter is 1000 cubic centimeters because 1 cubic centimeter = 1 mL
One Helium molecule (essentially one helium atom) has atomic mass 4 g/mol So for every 22400 cubic centimeters of volume, we have 4 grams of helium Density of helium = 4g / 22400 cm^3 = 1g / 5600 cm^3 
Volume of a sphere = (4/3)(pi)r^3 Volume of the outside sphere (the entire sphere) is (4/3)(pi)(R+T)^3 Volume of the inside sphere (the hollow region) is (4/3)(pi)R^3 
The difference for the volume of silver. (4/3)(pi)(R+T)^3 - (4/3)(pi)R^3 = (4/3)(pi)(3R^2T + 3RT^2 + T^3) 
The density of silver is 10.5g/cm^3 
So the mass of the silver is computed by:10.5*(4/3)(pi)(3R^2T + 3RT^2 + T^3) = (14*pi)(3R^2T + 3RT^2 + T^3) = (14pi)T(3R^2 + 3RT + T^2) 

Now for the mass of helium: volume x density = (4/3)(pi)R^3 (1/5600) = (pi/4200)R^3 

Set the two masses equal: (pi/4200)R^3 = (14pi)T(3R^2 + 3RT + T^2) R^3 = 58800*T(3R^2 + 3RT + T^2) R / T = 58800*(3R^2 + 3RT + T^2) / R^2 = 58800*( 3+T/R^2+(T/R)^2) 
then solve for xx = T / R 1/x = 58800*( 3+x/R+x^2) 1/58800 = x (3 + x/R + x^2) 1/58800 = 3x + x^3 x^3 + 3x - 1/58800= 0 x = ~ 5.66893x10^(-6)
6 0
3 years ago
J² - jk +k²= 7<br>J⁴ +j²k² + k⁴ = 133​
LekaFEV [45]

Answer: You can search it up...

Step-by-step explanation: Have a nice day!

4 0
3 years ago
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