Probabblity that the cube lands on 4 = 1/6
Probablity that the coin lands heads up = 1/2
Probablity of both happening = 1/2 * 1/6 = 1/12
The answer ur looking for is*
8
x
+
13 hope I’ve helped ;)
Step-by-step explanation:
m(x + n) = n
mx + mn = n
mx = n - mn
x = (n - mn)/m
x(a + b) = b(c - x)
ax + bx = bc - bx
ax + bx + bx = bc
x(a + b + b) = bc
x(a + 2b) = bc
x = bc/(a + 2b)
mx = n(m + x)
mx = mn+ nx
mx - nx = mn
x(m - n) = mn
x = mn/(m-n)
Answer:
f^-1(x) = 4(x+5)/3
Step-by-step explanation:
Let f(x) = y
So, y = (3/4)x - 5
y + 5 = (3/4)x
4(y+5)/3 = x
The steps are first to make a variable that holds the same value as the function, then from there you simplify and eventually make x the subject of the equation.
