First you compare the denomonators and see if they have any common multiples, then what you do to one side you do to the other so you multiply so you get the same number on both denomonators.finally you multipybthe same number you did ti he botto. to the top.p.s. your welcome

4 0

3 years ago

Let x denote the number of defective light bulbs in a randomly selected 20-count box from a local hardware store. The variable x

Molodets [167]

Answer:

Step-by-step explanation:

because it make the most sense

8 0

3 years ago

3/5 ÷ 4/5 = ???<br> A. <br> 3/4<br> B. <br> 2/5<br> C. <br> 7/9

Ahat [919]

Answer:

Option A

Step-by-step explanation:

⅗ ÷ ⅘

⅗ × 5/4

= 3/4

<h2>HOPE IT HELPS</h2>

6 0

3 years ago

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