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makvit [3.9K]
3 years ago
15

Solve The Equation 15 = 9 - 3a

Mathematics
2 answers:
Galina-37 [17]3 years ago
8 0
A= -2 ( hope that helps)
MAVERICK [17]3 years ago
5 0
2=A hope this helps
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Joey rode his bike 20 miles at a speed of 8 mph. How long did it take him?
Vlad1618 [11]
B) 2.5 hours , because 8 mph is 1 hour and the another 8mph is 1 hour 8+8mph =16mph 1+1hr=2hr half of 8 is 4mph is .5hr so therefore 8+8+4=20mph 1+1+ 30mins= 2.5hr
6 0
4 years ago
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an mark obthe meatin by 9 students of class 6 in exam is 50 among them the mark obtain by 8 student are 60, 40, 50, 30, 80, 40,
borishaifa [10]

Answer: 65

Step-by-step explanation:

Since the mean mark of the 9 students is 50. Their total marks will be:

= 9 × 50

= 450

Since the marks obtained by 8 students are given, we add the marks together and this will be:

= 60+40+50+30+80+40+45+40

= 385

The score of the 9th student will be:

= 450 - 385

= 65

7 0
3 years ago
Simone put $250 into her savings account that has an annual interest rate
Umnica [9.8K]
The other answers confuse me. 267.5 since 3.5=0.035 so 250x0.03.5=8.75x2=17.5+250
4 0
3 years ago
Duncan says since 6 is greater than 3 the number 65 is greater than 344 is he correct
zavuch27 [327]
No... 344 is greater than 65
6 0
4 years ago
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Which statements, if any, are true about these functions?
Firdavs [7]

Answer: C)  I, I and III

In other words, statements I through III are all true.

====================================================

Explanation:

Apply substitution to say that,

f(x) = 3x^3 + 2\\\\f(g(x)) = 3(g(x))^3 + 2\\\\f(g(x)) = 3\left(\sqrt[3]{\frac{x-2}{3}}\right)^3 + 2\\\\f(g(x)) = 3*\left(\frac{x-2}{3}\right) + 2\\\\f(g(x)) = x-2 + 2\\\\f(g(x)) = x\\\\

We can see that the cube root and cube exponents cancel each other out, and everything simplifies to simply x.

Now compute the other composite function, where g(x) is the outer function this time.

g(x) = \sqrt[3]{\frac{x-2}{3}}\\\\g(f(x)) = \sqrt[3]{\frac{f(x)-2}{3}}\\\\g(f(x)) = \sqrt[3]{\frac{3x^3 + 2-2}{3}}\\\\g(f(x)) = \sqrt[3]{\frac{3x^3}{3}}\\\\g(f(x)) = \sqrt[3]{x^3}\\\\g(f(x)) = x\\\\

Again, the cubing and cube root cancel each other out.

Since both f(g(x)) = x and g(f(x)) = x are true equations, this means that functions f(x) and g(x) are inverses of each other.

The two functions undo one another.

---------

As a simpler example, consider these two functions:

f(x) = x+5

g(x) = x-5

The f(x) function adds 5 to whatever the input is, and the g(x) goes in the opposite direction to subtract 5 to undo what f(x) did. For this example, you should find that f(g(x)) = x and g(f(x)) = x

Applying the composite of these inverses means that the final output is whatever the original input was. If we start with x = 87, then x+5 = 87+5 = 92, and then 92-5 = 87 which was the original input. Overall, no change has happened.

5 0
3 years ago
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