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telo118 [61]
2 years ago
12

Tell whether the equation has one, zero, or infinitely many solutions.9(x − 3) + 15 = 9x − 11.

Mathematics
2 answers:
romanna [79]2 years ago
7 0

Answer:

No solution

Step-by-step explanation:

9(x-3)+15= 9x-11

9x-27+15=9x-11

-15 on both sides

9x-27=9x-26

add 26 on both sides

9x -1=9x

add 1 on both sides

9x=9x+1

divide 9 on both sides

x=x+1/9

No solution

V125BC [204]2 years ago
5 0

Answer:

Zero solutions; there are no variables and thus there are no solutions

Step-by-step explanation:

We start out with the equation 9 (x - 3) + 15 = 9x - 11

Which simplifies to 9x - 27 + 15 = 9x - 11

The 9x terms cancel each other out, and we're left with 15 - 27 = -11

And we end up with -12 = -11, which is not true.

This tells us that the equation has zero solutions, because no matter what value we substitute for x, the equation will not be true.

You might be interested in
Un alumno multiplica un número por 32 en lugar de multiplicarlo por 23, obteniendo un producto mayor en 54 al producto original.
romanna [79]

Answer:

La suma de cifras del producto original es igual a 12.

Step-by-step explanation:

De acuerdo a la información proporcionada, si multiplicas un número "x" por 32 su resultado sería igual al producto original "y" más 54 dado que dice que se obtiene un producto mayor en 54 al producto original, lo que se puede expresar de la siguiente forma:

32x=y+54

Además, se puede inferir a partir del enunciado que si el número x se hubiera multiplicado por 23 el resultado habría sido el producto original que lo denominamos como "y", por lo que puedes decir que:

y=23x

Ahora puedes reemplazar y=23x en 32x=y+54 y despejar x:

32x=23x+54

32x-23x=54

9x=54

x=54/9

x=6

Finalmente, puedes reemplazar el valor de x en y=23x:

y=23x

y=23*6

y=138

Suma de cifras: 1+3+8 = 12

De acuerdo a esto, la respuesta es que la suma de cifras es igual a 12.

5 0
2 years ago
Use crayons to color to shows at least two of it's parts<br><br><br>​
Luden [163]

Answer:

im not exactly sure what you mean by that, could you please rephrase and expand on the pregunta

Step-by-step explanation:

5 0
1 year ago
A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions
faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3><u>Solution:</u></h3>

Given that  

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

<em><u>The area of rectangle is given as:</u></em>

\text {Area of rectangle }=length \times width

Area of rectangular parking lot = length of rectangular parking plot \times width of the rectangular parking

\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}

But it is given that Area of rectangular parking lot = 15000 square feet

\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}

Solving the above quadratic equation using quadratic formula

<em><u>General form of quadratic equation is  </u></em>

{ax^{2}+\mathrm{b} x+\mathrm{c}=0

And quadratic formula for getting roots of quadratic equation is

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}

\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet  

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

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KonstantinChe [14]
The estimated sum is 30.
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Which of the following is NOT a characteristic of a plane?
Brrunno [24]
It’s width can be measured (is not a characteristic of a plane)
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