Answer:
Step-by-step explanation:
AB = 8x + 5
BC = 5x² - 16
5x² - 16 = 8x + 5
5x² - 8x - 21 = 0
Quadratic formula
x = [8 ± √(8² – 4·5(-21))] / [2·5]
= [8 ± √484] / 10
= [8 ± 22] /10
= -1.4, 3
-1.4 is an extraneous solution.
x = 3
AB = 8x+5 = 29
AC = 58
I’m not for sure but I think it’s D good luck tho
If the equation of the absolute value function is f(x) = |x + 1| + 7, then the range of the function is -∞ < y ≤ 7
<h3>How to determine the range of the absolute value function?</h3>
<em>The question is incomplete, so I will provide a general explanation</em>
Assume that the absolute value function is given as:
f(x) = |x + 1| + 7
Set the absolute value to 0
f(x) ≥ 0 + 7
Evaluate
f(x) ≥ 7
This means that the smallest value of the function is 7
Hence, the range of the absolute value function is -∞ < y ≤ 7
Read more about range at:
brainly.com/question/10197594
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Answer:
x = 2
Step-by-step explanation:
6x - 10 = - 3x + 8
6x + 3x = 8 + 10
9x = 18
x = 18/9
x = 2
<span>A data point is 1.3 units above the line of best fit</span>
