Ask question

Ask question

All categories

3 years ago

11

Cos theta Root over 1 - cos square theta

1 answer:

Fittoniya [83]3 years ago

8 0

Answer:

${ \bf{ \cos \theta \sqrt{1 - { \cos }^{2} \theta } }} \\ { \sf{ = \cos \theta \sqrt{ { \sin }^{2} \theta} }} \\ { \sf{ = \cos \theta \sin \theta }} \\ { \sf{ = \frac{1}{2} \sin(2 \theta) }}$

You might be interested in

What is the value of x

vichka [17]

Answer:

Step-by-step explanation:

The triangles are similar.

(x-6)/3 = x/6

x = 15

4 0

3 years ago

A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer

Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

$L_A \to$ length of play area A

$W_A \to$ width of play area A

$L_B \to$ length of play area B

$W_B \to$ width of play area B

$x \to$ Area of A

$y \to$ Area of B

From the question, we have the following:

$L_A = 1 + 4W_A$

$W_B = 2 + W_A$

$L_B = 2 + 3W_B$

$x = y$

The area of A is:

$x = L_A * W_A$

This gives:

$x = (1 + 4W_A) * W_A$

Open bracket

$x = W_A + 4W_A^2$

The area of B is:

$y = L_B * W_B$

$y = (2 + 3W_B) * ( 2 + W_A)$

Substitute: $W_B = 2 + W_A$

$y = (2 + 3(2 + W_A)) * ( 2 + W_A)$

Open brackets

$y = (2 + 6 + 3W_A) * ( 2 + W_A)$

$y = (8 + 3W_A) * ( 2 + W_A)$

Expand

$y = 16 + 8W_A + 6W_A + 3W_A^2$

$y = 16 + 14W_A + 3W_A^2$

We have that:

$x = y$

This gives:

$W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2$

Collect like terms

$4W_A^2 - 3W_A^2 + W_A -14W_A - 16 =0$

$W_A^2 -13W_A - 16 =0$

Using quadratic calculator, we have:

$W_A = -14.1$ or $W = 1.13$ --- approximated

But the width can not be negative; So:

$W = 1.19$

7 0

3 years ago

Solution for 20=v+9-16 equation

gulaghasi [49]

Answer:

If you are solving for v, v= 27 cause 27+9=36 then you subtract 16 from 36 and it equals 20.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The sum of two numbers is zero. When 13 times the smaller number is added to 8 times the larger, the result is 2. Find the two n

lesya [120]

Answer:

x = (2/5); y = (-2/5)

Step-by-step explanation:

x + y = 0

13x + 8y = 2

Multiply so the "x" variables are opposite with the same absolute value.

(-13) x + y = 0 (-13) ⇒ -13x - 13y = 0

(1) 13x + 8y = 2 (1) ⇒ 13x + 8y = 2

Add the two equations.

(13x - 13x) + (8y - 13y) = (2 - 0)

-5y = 2

Divide both sides by -5

y = $-\frac{2}{5}$

Plug the value of "y" into either equations.

x + $(-\frac{2}{5})$ = 0

Add $\frac{2}{5}$ to both sides.

x = $\frac{2}{5}$

6 0

3 years ago

If two planes intersect, then their intersection is a point true or false

salantis [7]

I believe that it is true

Step-by-step explanation:

sorry if im wrong

7 0

3 years ago

Read 2 more answers