1. -3
2. 28
3. 88
4. -5
5. -28
Answer:
Triangle APB is an isosceles triangle ⇒ 3rd answer
Step-by-step explanation:
* Lets explain the how to solve the problem
- ABCD is a square
∴ AB = BC = CD = AD
∴ m∠A = m∠∠B = m∠C = m∠D = 90°
- DPC is equilateral triangle
∴ DP = PC = DC
∴ m∠DPC = m∠PCD = m∠CDP = 60°
- In the Δs APD , BPC
∵ AD = BC ⇒ sides of the square
∵ PD = PC ⇒ sides of equilateral triangle
∵ m∠ADB = m∠BCP = 30° (90° - 60° = 30) ⇒ including angles
∴ Δs APD , BPC are congregant ⇒ SAS
- From congruent
∴ AP = BP
∴ Triangle APB is an isosceles triangle
Hello!
Answer:
3/4x = -24
To isolate the "x" variable, divide both sides by 3/4 (multiply by its reciprocal, or 4/3)
3/4x · 4/3 = -24 · 4/3
x = (-24 · 4) / 3
x = -32.
Answer:
AB = 5.2
AC = 5.2
m∠3 = 30 degrees
, m∠4 = 30 degrees
Step-by-step explanation:
Triangle ABO and ACO are both 30 60 90 triangles and are equal
Therefore If we have two sides then we can figure out the last side
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