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3 years ago

Cos theta Root over 1 - cos square theta

Mathematics

1 answer:

Fittoniya [83]3 years ago

8 0

Answer:

${ \bf{ \cos \theta \sqrt{1 - { \cos }^{2} \theta } }} \\ { \sf{ = \cos \theta \sqrt{ { \sin }^{2} \theta} }} \\ { \sf{ = \cos \theta \sin \theta }} \\ { \sf{ = \frac{1}{2} \sin(2 \theta) }}$

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Masha biked 20km 20 minutes faster than Dasha biked 20km. Find the speed of each cyclist if one biked 2km/h faster than the othe

motikmotik

Answer:

12 km/h and 10 km/h

Step-by-step explanation:

Let the speed of Masha = s, speed of Dasha = d

Distance = 20 km
Time difference = 20 min = 1/3 hr
Speed difference = 2 km/h

As per above info we get following equations:

s = d + 2
20/s + 1/3 = 20/d

Substitute s and solve for d:

20/(d + 2) + 1/3 = 20/d

Get rid of fraction by multiplying all terms by 3d(d + 2):

60d + d(d + 2) = 60(d + 2)
60d + d² + 2d = 60d + 120
d² + 2d = 120
d² + 2d + 1 = 121
(d + 1)² = 11²
d + 1 = 11
d = 10

Find s:

s = 10 + 2 = 12

The answer is

Masha's speed 12 km/h and Dasha's speed 10 km/h

3 0

3 years ago

What is the greatest value shown on the box-and-whisker plot?

Rainbow [258]

The greatest value shown on the dot and whisker plot is c. 50

4 0

3 years ago

Plz help me with this

goldenfox [79]

Area of triangle=1/2(base×height)
360=1/2((4x-2)(7x+5))
720=(4x-2)(7x+5)
FOIL the binomial
720=28x^2+6x-10
Bring 720 to the other side
28x^2+6x-10-720=0
28x^2+6x-730=0
Factor 2 out
2(14x^2+3x-365)=0
Factor 2(14x+73)(x-5)=0
x-5=0
x=5
It can't be 14x-73=0 because the length can't be negative.
You're welcome.

5 0

3 years ago

What is the exact area of a circle with a diameter of 10 cm? a. 5πcm^2 b. 10πm^2 c. 25πcm^2 d. 100πcm^2

dalvyx [7]

Answer:

Step-by-step explanation:

a= $\pi$ r^2

To find the radius, divide the diameter by 2

r=d/2

r=10/2

r=5

a= $\pi$ r^2

a= $\pi$ 5^2

a=25 $\pi$

So, choice C is correct

Hope this helps! :)

4 0

3 years ago

A rectangle has length that is 5 less than 2 times the width. Write an expression for the area of the rectangle.

a_sh-v [17]

We are given a relationship between the sides of a rectangle, that is, the length of one of its sides is 5 less two times its width, and we are asked to find an expression for the area. Let's remember that the area of a rectangle is equal to the product of the length of its side by its width. Let "w" be the length of the rectangle and "L" its lenght, then the area is given by the following formula: