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julia-pushkina [17]

3 years ago

15

Meg is 6 years older than Victor. Meg's age is 2 years less than five times Victor's age. The equations below model the relation

ship between Meg's age (m) and Victor's age (v):
m = v + 6
m = 5v − 2

Which is a possible correct method to find Meg's and Victor's ages?

Solve m + 6 = 5m − 2 to find the value of m.
Write the points where the graphs of the equations intersect the x axis.
Solve v + 6 = 5v − 2 to find the value of v.
Write the points where the graphs of the equations intersect the y axis.

1 answer:

nekit [7.7K]3 years ago

6 0

Answer:

Option C

Step-by-step explanation:

Step 1: Find the correct method

Option A is incorrect because we don't have m + 6 and 5m - 2

Option B is incorrect because that wouldn't show us the correct value

Option C is correct, once we solve for v, we can plug in v and get the value of m. For example: v + 6 = 5v - 2 → v + 8 = 5v → 8 = 4v → 2 = v. Then we plug it into the other equation m = 2 + 6 → m = 8

Option D is incorrect because that wouldn't show us the correct value.

Answer: Option C

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Please answer right away

Andreas93 [3]

Answer:

20 miles with an error margin of ± 8 miles

Step-by-step explanation:

The margin of error of a result is the range in which an error can vary. To find the margin of error between both distances we have to

28-12 = 16, that is, the variation of the result has a range of 16 miles. So we will look for the midpoint of both distances

(X2-X1)/2+X1=(28-12)/2+12=16/2+12=8+12=20

So from this midpoint the value can vary between 8 points below and 8 points above that would cover the difference of 16 miles that we observed at the beginning

In this way, the correct answer is 20 miles with an error margin of ± 8 miles

Done

8 0

3 years ago

What is the equation of the graphed function?

choli [55]

Answer:

( 2 - x )^2

Step-by-step explanation:

8 0

3 years ago

Plz answer both for 10 points.!!! Thx for the help.

ratelena [41]

Both questions make use of the formula for the area of a triangle:
.. A = (1/2)*b*h

23. A = (1/2)*b*h
.. A = (1/2)*x*7 . . . . substitute the given values
.. A = 3.5x . . . . . . . simplified

24. A = (1/2)*b*h
.. 84.5 = (1/2)*13*h . . . . . substitute the given values

.. 2*84.5/13 = h = 13 . . . .solve for h
The height of the triangle is 13 cm.

4 0

3 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is:

$T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20$

From the first equation:

$d_1 = 40t_1$

$t_1 = \frac{d_1}{40}$

Replacing in the second equation:

$60 = \frac{d_1 - 20}{t_1 - 2}$

$d_1 - 20 = 60t_1 - 120$

$d_1 - 20 = 60\frac{d_1}{40} - 120$

$d_1 = \frac{3d_1}{2} - 100$

$d_1 - \frac{3d_1}{2} = -100$

$-\frac{d_1}{2} = -100$

$\frac{d_1}{2} = 100$

$d_1 = 200$

Thus, the total distance is:

$T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380$

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0

2 years ago

A light bulb consumes 960 watt hours per day how long does it take to consume 4320 watt hours

VARVARA [1.3K]

Since we need to determine how long it takes for the watt hours to consume 4320 watt hours, we would need to divide.

We would simply divide.

4320/950= 4.5

The 4.5 represents how long it would take for the light bulb to consume 4320 watt hours.

Therefore, the answer would be 4.5 days.

<u>Answer</u>

4.5 days

<u>Recap</u>

1. We read the problem and determined that in order to solve the problem we would need to divide.

2. We then divided 4320/960= 4.5

3. We came to the conclusion that 4.5 days would be the answer.

7 0

3 years ago