What is the equation of the graphed function?
1 answer:
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Answer:
The values in the table, taking into account the quadratic equation, are:
- x -3 -2 -1 0 1 2 3 4
- y <u>16</u> 9 <u>4</u> 1 <u>0</u> 1 <u>4</u> 9
Step-by-step explanation:
To obtain the values of the table, you must use the quadratic equation given:
- <u>y = x^2 - 2x + 1</u>
Now, you must replace the x with the one that is above the value you want to find, in the first case, we're gonna replace the value x with -3:
- y = x^2 - 2x + 1
- y = (-3)^2 - 2*(-3) + 1
- y = 9 + 6 + 1
- <u>y = 16</u>
When x is -1
- y = x^2 - 2x + 1
- y = (-1)^2 - 2*(-1) + 1
- y = 1 + 2 + 1
- <u>y = 4</u>
When x is 1
- y = x^2 - 2x + 1
- y = (1)^2 - 2*(1) + 1
- y = 1 - 2 + 1
- <u>y = 0</u>
When x is 3:
- y = x^2 - 2x + 1
- y = (3)^2 - 2*(3) + 1
- y = 9 - 6 + 1
- <u>y = 4</u>
At last, the graph must be as the attached picture I give you, but <u><em>remember in y-axis you must use 1 cm as unit and in the x-axis you must use 2 cm as unit, in this form, the graph will not be so elongated as the picture I attach, It would be wider</em></u>.
The correct standard form of the equation of the parabola is:
= 4(y - 3).
An equation of a curve that has a point on it that is equally spaced from a fixed point and a fixed line is referred to as a parabola. The parabola's fixed line and fixed point are together referred to as the directrix and focus, respectively. It's also crucial to remember that the fixed point is not located on the fixed line. A parabola is a locus of any point that is equally distant from a given point (focus) and a certain line (directrix). An essential curve of the coordinate geometry's conic sections is the parabola.
For the given question,
Vertex of parabola is (-3,3)
Thus, the equation of the parabola is:
= 4(y-3)
Learn more about parabolas here:
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