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Serggg [28]
2 years ago
15

A student said that x = 4 was not a solution to the question 3(x -6) = -8

Mathematics
1 answer:
Morgarella [4.7K]2 years ago
6 0

Answer:

Step-by-step explanation:

3 (4 -6) = -8 is correct.  The next step is to combine 4 and -6, obtaining

3(-2)

and this 3(-2) should equal -6, which is not the same as -8.

3(4 - 6) = 12 - 18, which differs from the student's solution.  This is the reason for the wrong answer.

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Angle MNO is formed by segments MN and NO on the following coordinate grid:
tekilochka [14]

Answer: m∠ M′N′O′ = 90 degrees

Step-by-step explanation: Hope that helps ! I am not sure if  I am right but I think I am !

3 0
2 years ago
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Thats the question ​
elixir [45]

Answer:

160 in ^2

Step-by-step explanation:

First we need to find the area of each shape and add them together

1. Triangles:

The formula for a triangle is (base x height)/2, so we can replace them as (5 * 4)/2 * 2( Because there are two triangles), so therefore the two triangles will add up to 20 inches

2. The Rectangles

<u>The Big Rectangle:</u>

The big rectangle is just <em>l x w </em> or 5 * 20 which is 100

<u>The small rectangle:</u>

To find the width of the small rectangle you have to do 20 - (5 + 5) because we are not including the triangles. 20 - (5 +  5) = 10, so that would be 10 * 4 = 40.

3.Add them together

20 + 100 + 40 = 160 inches ^2

Hope this helps!!!

4 0
2 years ago
Need help with this.
stepan [7]
Third one down. you can tell just by the first two coordinates
6 0
2 years ago
Write the equation of the line in point slope form that passes through the given point (4,-1);m=-6
Rashid [163]
The equation will be -6(x-4)-1
4 0
3 years ago
Read 2 more answers
This Question: 1 pt
zhenek [66]

\huge{ \mathfrak{  \underline{ Answer }\:  \:  ✓ }}

Angles forming linear pair are :

\mathrm{\angle EFG  \:  \: and \:  \:   \angle GFH}

And we know, they are supplymentary

  • \mathrm{\angle EFG  \:   +  \:   \angle GFH}  = 180 \degree
  • 3n +1 9 \degree+ 2n + 36\degree = 180 \degree
  • 5n + 55\degree = 180\degree
  • 5n = 125\degree
  • n = 25\degree

So, the measures of the given angles are :

  • \mathrm{\angle EFG } = 3n + 19
  • \mathrm{ \angle EFG = (3  \times 25\degree)  + 19}
  • \mathrm{ \angle EFG = 75 \degree+ 19\degree}
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And

  • \mathrm{ \angle GFH = 2n + 36}
  • \mathrm{ \angle  GFH = (2 \times 25\degree) + 36\degree}
  • \mathrm{ \angle GFH = 50\degree + 36\degree}
  • \mathrm{ \angle GFH = 86\degree }

_____________________________

\mathrm{ ☠ \: TeeNForeveR \:☠ }

6 0
3 years ago
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