<h3>
Answer: 6.282</h3>
Explanation:
Refer to the table below. I've added a third row where I multiplied each x value with its corresponding frequency value f. We can refer to this row as the xf row.
Once we know the xf values, we add them up to get 245.
We'll then divide that result over the sum of the frequency values (add everything in the second row). The sum of the frequency values is 39.
So the mean is approximately: 245/39 = 6.282051 which rounds to 6.282
Notice that this mean value is fairly close to the x value which has the highest frequency.
Answer:
3N + 10
Step-by-step explanation:
Answer:
x < 2
Step-by-step explanation:
Answer:
107%
Step-by-step explanation:
because if we look at the x-axis, Discount (%)
and look at 35 which is between 30 and 40
and start going up we get near 100
so
107%
or?
we use the two points and with that we find the slope first
plug in (20,62) and (10,32)
equals
simplify to 3
then we use
y - y1 = m (x - x1)
y - 62 = 3 (x - 20)
y - 62 = 3x - 60
add 60 from both sides
y - 2 = 3x
add 2 to both sides
y=3x+2
then plug in 35
y= 3(35) + 2
which is
107
Answer:
About 609,000 Cowboy stadiums could fit inside of Mount Everest
Step-by-step explanation:
we have
The estimate volume of Mount Everest is at around 
The Dallas Cowboys Stadium has a volume of 
step 1
Convert ft³ to km³
we know that
1 km=3,280.84 ft
so
step 2
To find how many Cowboy stadiums could fit inside of Mount Everest, divide the volume of Mount Everest by the volume of the Dallas Cowboys Stadium
Round to the nearest Thousands
The volume of Mount Everest is about 609,000 times greater than the volume of the Dallas Cowboys Stadium
