All categories

2 years ago

What is the difference in the Volume Formula for a prism and a pyramid. *

1 answer:

4 0

Answer:the volume of a prism is the area of the base times the height of the prism. The volume of the pyramid has the same base area and height as the prism, but with less volume than the prism. The volume of the pyramid is one third the volume of the prism.

Step-by-step explanation:

i hope this helps

You might be interested in

Your family goes to a southern style restaurant for dinner. There are 6 people in your family. Some order the chicken dinner for

Len [333]

Ok. You can use equations to find out what number of each meal was eaten.

x*14+y*17=99

If you solve for x and y (I used guess and check- there's only a few possible combinations) and got one chicken dinner and five steak dinners.

7 0

3 years ago

Read 2 more answers

The solution set for 7q^2-28=0

kherson [118]

7q² - 28 = 0
   + 28 + 28
   7q² = 28
       7 7
   q² = 4
      q = ±4
      q = 4 or q = -4

Solution Set: {±4} and {q|q = 4 or q = -4}

8 0

2 years ago

The school water fountain can only fill 3/4 of a jug at a time. With this amount of water, Mr. Kern can water 3/8 of his plants.

Vesnalui [34]

Answer:

$\frac{3}{4} = \frac{3}{3} \\ \frac{3}{8} = x \\ x = \frac{3}{8} \times \frac{4}{3} \\ x = \frac{1}{2}$

5 0

2 years ago

Travelers who fail to cancel their hotel reservations when they have no intention of showing up are commonly referred to as no-s

notsponge [240]

Answer:

a) 0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) 0 is the most likely value for X.

Step-by-step explanation:

For each traveler who made a reservation, there are only two possible outcomes. Either they show up, or they do not. The probability of a traveler showing up is independent of other travelers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

No-show rate of 10%.

This means that $p = 0.1$

Four travelers who have made hotel reservations in this study.

This means that $n = 4$

a) What is the probability that at least two of the four selected will turn to be no-shows?

This is $P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

$P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.0486 + 0.0036 + 0.0001 = 0.0523$

0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) What is the most likely value for X?

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.1)^{0}.(0.9)^{4} = 0.6561$

$P(X = 1) = C_{4,1}.(0.1)^{1}.(0.9)^{3} = 0.2916$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

X = 0 has the highest probability, which means that 0 is the most likely value for X.

7 0

2 years ago

using the giving information to write an equation. let X represent the number described in the exercise.then solve the equation

ANEK [815]

A number is multiplied by 8 and the result is 28.

A number= x.

8(x)= 28

Divide both sides by 8.

28/8= 3.5

x= 3.5

I hope this helps!
~kaikers

5 0

3 years ago