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Hunter-Best [27]
3 years ago
12

Anyone know how to do this?

Mathematics
1 answer:
Pavel [41]3 years ago
4 0

Answer:

5 = 16 - 11 \\  so \: \\  {x}^{2}  - 8x + 16 - 11\\  \\  {x}^{2}  - 8x + 16 = (x - 4)^{2}  \\ \\  (x - 4)^{2}  - 11

Step-by-step explanation:

I hope that is useful for you :)

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The length of the hypotenuse of a 30 - 60 - 90 triangle is 16 cm.
xeze [42]

Answer:

8, 8x square root of 3

Step-by-step explanation:

16=2x

x=8

4 0
3 years ago
Door is 77 inches high, 35.25 inches wide and 1,75 inches thick how much paint is needed
Leviafan [203]
If you wanted to paint the entire door (even the top and bottom which people don't usually paint)

the surface area is
SA=2(LW+LH+WH)
where L=length, W=width and H=height

given
L=35.25
W=1.75
H=77

SA=2(35.25*1.75+35.25*77+1.75*77)
SA=2(61.6875+2714.25+134.75)
SA=2(2910.6875)
SA=5821.375

you need enough paint to cover 5821.375 square inches of door
7 0
3 years ago
A water tank is 1/8 full the tank is 3/4 full when 42 gallons are added to the tank how much water was originally in the tank
masha68 [24]
<span>A water tank is 1/8 full. The tank is 3/4 full when 42 gallons are added to the tank. How much water was originally in the tank? (I rewrote it, your wording was messed up)

3/4 = 6/8 
1/8 + 6/8 = 7/8 = 42 gallons
42 divided by 8 = 5 1/4

So, the answer is 5 1/4. The tank originally 5.25 gallons of water.</span>
8 0
3 years ago
A rectangular parking lot has a length that is 5 yards greater than the width the area of the parking lot is 300 yd.² find the l
ArbitrLikvidat [17]

Answer:

width=5yd and length=10yd

Step-by-step explanation:

To solve this problem, you need to start by asking what you do and don't know (always where to start with word problems)

We know that Area (A) = Length (L) * Width (W)

You know Area (A) = 50 sq. yds.

You don't know anything about the width, so let's just say Width (W) = x

And you know that the length is 5 yds longer than the width, so L = W + 5yd and, since W = x, we can say L = x + 5yd

Now, we recall that A = L * W, and, since A = 50, we can say 50 sq yd = L * W.

Well, now just plug in. What does W equal and L equal?

From above we plug in and can say that 50 sq yd = x * (x + 5 yd).

Multiply it out and you get 50 = x^2 + 5x (removing units for a moment so they don't clutter the lines).

Now there are a number of ways to solve this. You can tell (because of the "x^2") that it is quadratic. So let's get it equal to zero:

0 = x^2 + 5x - 50

Now you can factor it, use your quadratic formula, or (if you hated yourself) do it as a completing the square problem. I'm going to factor.

I can see from going through a list in my head that the factors 10 and -5 multiply to -50 and add to 5, so I know that

0 = x^2 + 5x - 50 = (x + 10)(x - 5)

And so you know that x = -10 or 5.

Well, you know the parking lot cannot be -10 yd long. So we must say that W = x = 5, and, since L = W + 5, then L = 5+5 = 10. So your width is 5 yd and length is 10 yd.

<h2>mark me brainlist</h2>
6 0
2 years ago
You can perform 6 push-ups in 24 seconds. Write and
algol13

Answer:

480 push ups

Step-by-step explanation:

24/6 = 4

meaning they are doing 4 push ups per second, this is your slope

the equation of your line is y = 4x, you can graph this using a table of values (i attached a graph tho)

2 minutes = 120s

y = 4(120)

y = 480

7 0
3 years ago
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