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pshichka [43]
3 years ago
13

What does the statement that follows do? double gallons[6] = { 12.75, 14.87 }; a. It assigns the two values in the initializatio

n list to the first two elements but leaves the other elements with the values currently in memory. b. It assigns the two values in the initialization list to the first and second elements, third and fourth elements, and fifth and sixth elements. c. This statement is invalid. d. It assigns the two values in the initialization list to the first two elements and default values to the other elements.
Computers and Technology
1 answer:
Serhud [2]3 years ago
3 0

Answer:

It assigns the two values in the initialization list to the first two elements and default values to the other elements.

Explanation:

Given

The array initialization

Required

Interpret the statement

double gallons[6] implies that the length/size of the array gallons is 6.

In other words, the array will hold 6 elements

{12.75, 14.87} implies that only the first two elements of the array are initialized ; the remain 4 elements will be set to default 0.

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Is recursion ever required to solve a problem? What other approach can you use to solve a problem that is repetitive in nature?
Setler79 [48]

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No you can not tell that recursion is ever required to solve a problem.

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Iteration is also another form of repetitive approach we follow to solve that kind of problems.

But the difference between recursion and iteration is :

  • In recursion we call the function repeatedly to return the result to next level.
  • In iteration certain bunch of instructions in a loop are executed until certain conditions met.

Explanation:

For example in the Fibonacci sequence problem, to find f_{n}, we need to compute f_{n-1} and f_{n-2} before that.

  • In case of recursion we just call the method Fibonacci(n) repeatedly only changing the parameter Fibonacci(n-1), that calculates the value and return it.

                           Fibonacci(n)

                           1. if(n==0 or n==1)

                           2.       return 1.

                           3.else

                           4.      return( Fibonacci(n-1)+Fibonacci(n-1) )

  • But in case of iteration we run a loop for i=2 to n, within which we add the value of current f_{i-1} and f_{i-2} to find the value of f_{i}

                           Fibonacci(n)

                           1. if(n<=2)

                           2.    result = 1

                           3.     else

                           4. result1 =1 and result2=1.

                           5.      {  result = result1 +result2.

                           6.         result1= result2.

                           7.         result2 = result.

                           8.      }

                           9.  output result.

8 0
3 years ago
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