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maksim [4K]
3 years ago
5

Carly purchased 9.5 pints of ice cream for a party. If each guest will be served exactly 3/5 pints of ice cream, what is the gre

atest number of guests that Carly can serve?
Mathematics
2 answers:
fgiga [73]3 years ago
6 0
Answer:‍♀️
Hope this helped
aivan3 [116]3 years ago
3 0

Answer:

15.8333333333

Step-by-step explanation:

9.5 divied by 3.5

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Find the area of the figure. (Sides meet at right angles.) <br>​
ikadub [295]

Answer:

44ft^2

Step-by-step explanation:

Break the shape into 3 rectangles, two 3 by 2's and one 4 by 8. (Get 4 by subtracting 3 from 7 for the left and right most side)

3 x 2 = 6 ft^2

since there's two rectangles you end up 6 + 6 so you get 12 ft^2

then 4 x 8 = 32 ft^2

add 32 and 12, get 44 ft^2

8 0
2 years ago
Y - x = 4<br><br><br> please help!!
UNO [17]
Add the x to both sides and it turns into Y = x + 4. If this isn't what you're looking for, please provide the answer choices.
6 0
4 years ago
Martina spends $15 each time she travels the toll roads. She started the month with $225 in her toll road account. The amount, A
PolarNik [594]

Answer:

$70 is what he would have left. Since each trip is $14 you would multiply that by the amount of times he went which was 11. 14x11 is $154. But you need what he has left so you take his total amount $224-$154 and get $70.

Part b.) 16 times. He has $224 total. You want to find out how many times he can go on the tool roads. We know the toll roads cost $14 each time. So you do $224/14 and get an even amount of 16. He would be able to use it 16 times before he have no money left.

Step-by-step explanation:

6 0
2 years ago
Does anyone know the answer to this help fast!
Paraphin [41]
180-90=3x
90=3x
X=30

90+x+y=180
90+30+y=180
120+y=180
Y=60
6 0
3 years ago
Read 2 more answers
Law of radicals
andrey2020 [161]

Answer:

1)  \sqrt{x^7}=x^{\frac{7}{2}

2)  \sqrt[3]{y^5}=y^{\frac{5}{3}

3) \sqrt[5]{a^{12}}=a^{\frac{12}{5} }

4) \sqrt[4]{z^{9}}=z^\frac{9}{4}

Step-by-step explanation:

1) \sqrt{x^7}

We know that \sqrt{x}=x^{\frac{1}{2}

So, \sqrt{x^7}=x^{\frac{7}{2}

2) \sqrt[3]{y^5}

We know that \sqrt[3]{x}=x^{\frac{1}{3}

So, \sqrt[3]{y^5}=y^{\frac{5}{3}

3) \sqrt[5]{a^{12}}

We know that \sqrt[5]{x}=x^{\frac{1}{5}

So, \sqrt[5]{a^{12}}=a^{\frac{12}{5} }

4) \sqrt[4]{z^{9}}

We know that \sqrt[4]{x}=x^{\frac{1}{4}

So, \sqrt[4]{z^{9}}=z^\frac{9}{4}

6 0
3 years ago
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