There is not enough information to give a numerical answer.
Let t=number of ten dollar bills.
"he has twice as many dimes as he has 10 dollar bills", so the amount A is
A=10*t+0.1*(2t)
"he has twice as many pennies as he has dimes"
A=10*t+0.1*(2t)+0.01*4t
"chris has twice as many 1 dollar bills as pennies"
A=10*(t)+0.1*(2t)+0.01*(4t)+1*(8t)
=18.24t
Therefore the total amount Chris has is 18.24 times the number of $10 bills he possesses.
Answer:
20
Step-by-step explanation:
0 to 1 = a difference of 1
1 to 2 = a difference of 2-1 = 1
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2 to 4 = a difference of 2
4 to 6 = a difference of 2
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6 to 9 = a difference of 3
9 to 12 = a difference of 3
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12 to 16 = a difference of 4
16 to 20 = a difference of 4
2x + 5 = 15 - (-49) x 5
combine like terms
2x + 5 = 320
subtract 5 from each side
2x = 315
divide by 2 on each side
x = 157.5
5-x
If your asking for it in numerical form.
Answer:
4
Step-by-step explanation:
You need to find XYW
<xYW = <XYZ - <WYZ
<XYW = 128 - 85
<XYW = 43
12x - 5 = 43 Add 5 to both sides
12x = 43 + 5
12x = 48 Divide by 12
x = 48/12
x = 4
