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Taya2010 [7]
3 years ago
12

A new video game is expected to sell 130 copies the first hour at a local game store. After that, the sales will follow the func

tion s(x) = 9(x − 1) where x is the number of hours. What is the function that shows total sales, including the first hour?
A) s(x) = 130 + 9(x − 1)
B) s(x) = 9(x − 1) − 130
C) s(x) = 130x − 9
D) s(x) = 130 − 9(x − 1)
Mathematics
2 answers:
lapo4ka [179]3 years ago
8 0

Answer:

s(x) = 130 + 9(x-1)

Step-by-step explanation:

Video games sold in first hour = 130

After the first hour the sales will follow the function:

s(x) = 9(x-1)

Where x is the number of hours.

So, in x hours hours video games sold = 9(x-1)

So, total video games sold (including first hour) = 130+9(x-1)

Thus the function that shows total sales, including the first hour:

s(x) = 130 + 9(x-1)

Hence Option A is correct : s(x) = 130 + 9(x-1)

suter [353]3 years ago
4 0
The answer is A I believe. 

At hour 1, the equation must equal 130,

therefore s(1) = 9(1-1) + 130
                s(1) = 9(0) + 130
                s(1) = 130

then so on when 
s(2) = 9(2-1) + 130
s(2) = 139

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Answer:

We conclude that the population mean is not equal to 17.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 17

Sample mean, \bar{x} = 14.12

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 4

First, we design the null and the alternate hypothesis

H_{0}: \mu = 17\\H_A: \mu \neq 17

We use Two-tailed z test to perform this hypothesis.

a) Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{14.12 - 17}{\frac{4}{\sqrt{40}} } = -4.5536

b) P-value can be calculated from the standard z-table.

P-value = 0.0000

c) Since the p-value is less than the significance level, we reject the null hypothesis and accept the alternate hypothesis. Thus, the population mean is not equal to 17

d) Now, z_{critical} \text{ at 0.05 level of significance } = \pm 1.96

e) Rejection Rule:

We reject the null hypothesis if it is less than lower critical value and greater than the upper critical value

If the z-statistic lies outside the acceptance region which is from -1.96 to +1.96, we reject the null hypothesis.

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Answer:

The answer is GE

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A football is kicked toward an end zone with an initial vertical velocity of 30 ft/s. The function h(t) = -16+ 30t models the he
Ulleksa [173]

Answer:

A. The football does not reach a height of 15ft

Step-by-step explanation:

Given

h(t) = -16t^2 + 30t

Required

Determine which of the options is true

The option illustrates the height reached by the ball.

To solve this, we make use of maximum of a function

For a function f(x)

Such that:

f(x) = ax^2 + bx + c:

f(\frac{-b}{2a}) = maximum/minimum

i.e we first solve for \frac{-b}{2a}

Then substitute \frac{-b}{2a} for x in f(x) = ax^2 + bx + c

In our case:

First we need to solve \frac{-b}{2a}

Then substitute \frac{-b}{2a} for t in h(t) = -16t^2 + 30t

By comparison:

b = 30

c = -16

\frac{-b}{2a} = \frac{-30}{2 * -16}

\frac{-b}{2a} = \frac{-30}{-32}

\frac{-b}{2a} = \frac{30}{32}

\frac{-b}{2a} = \frac{15}{16}

Substitute \frac{15}{16} for t in h(t) = -16t^2 + 30t

h(\frac{15}{16}) = -16(\frac{15}{16})^2 + 30(\frac{15}{16})

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h(\frac{15}{16}) = -(\frac{225}{16}) + \frac{450}{16}

h(\frac{15}{16}) = \frac{-225 + 450}{16}

h(\frac{15}{16}) = \frac{225}{16}

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This implies that the maximum height reached is 14.0625ft.

So, the option that answers the question is A because 14.0625 < 15

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