Answer:
an = -3 · an - 1 where a1 = -1.
Step-by-step explanation:
The first term a1 = -1 and the common ratio is -3 so ecah term is formed form the previous one by multiplying by -3.
Answer:
A. 3 < t < 9
Step-by-step explanation:
When the particle is moving to the right, the velocity is positive.
To find the velocity, take the derivative of s(t) with respect to t.
s(t) = -t³/3 + 13t²/2 − 30t
s'(t) = -t² + 13t − 30
Find when the velocity is 0.
0 = -t² + 13t − 30
0 = t² − 13t + 30
0 = (t − 3) (t − 10)
t = 3, 10
Check the sign of s'(t) in each interval.
0 < t < 3, s'(t) < 0
3 < t < 9, s'(t) > 0
The particle moves to the right when 3 < t < 9.
Answer:
LCM of 3, 5, and 6 is the smallest number among all common multiples of 3, 5, and 6. The first few multiples of 3, 5, and 6 are (3, 6, 9, 12, 15 . . .), (5, 10, 15, 20, 25 . . .), and (6, 12, 18, 24, 30 . . .) respectively. There are 3 commonly used methods to find LCM of 3, 5, 6 - by division method, by prime factorization, and by listing multiples.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Uhm the third one number 3
Answer:
point slope form: y + 4 = 3/8 (x + 5) slope intercept: y = 3/8x - 17/8
Step-by-step explanation:
y2 - y1 / x2 - x1
-1 - (-4) / 3 - (-5)
slope = 3/8
y + 4 = 3/8 (x + 5)
y = 3/8x + b
-1 = 3/8(3) + b
-1 = 9/8 + b
-17/8
y = 3/8x - 17/8
