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Igoryamba
2 years ago
10

Hi can some one please help me with question b please

Mathematics
1 answer:
creativ13 [48]2 years ago
7 0

Answer:

a=28200

b=39200

Step-by-step explanation:

ok use google

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An isosceles triangle has side lengths of 15.6 units and 20.33 units. What is the greatest possible value of the perimeter of th
ArbitrLikvidat [17]

Answer:

56.26

Step-by-step explanation:

An isosceles triangle has two sides that are the same length, and one side that is the same length. We have two sizes, so two find the greatest possible perimeter we must assume that the greater size is the value for the two sides, and the smaller size the value for the single side. In other words:

x = 15.6 + 2(20.33)

x = 56.26

6 0
1 year ago
Kyle held a balloon 8ft off the ground above his head and Ava is standing 15 feet directly to g the right of Kyle how far is Ava
ryzh [129]

Answer:

17

Step-by-step explanation:

Pythagorean theory baby! Okay so the Pythagorean theory is a² + b² = c² so lets draw a triangle and label our sides. So we know 8² + 15² = c² so I'm going to find the square root of all of our numbers. We get 64 + 225 = c² so then add 64 + 225 = 289 then I take the square root of 289 which equals 17 . This answer also makes sense because out hypotenuse should always be bigger then the legs.

I'm pretty sure thats right, Hope this helps.

5 0
3 years ago
The following graph describes function 1, and the equation below it describes function 2. Determine which function has a greater
Sergio039 [100]

Answer:

A.) Function 1 has the larger maximum at (4, 1).

Step-by-step explanation:

No step-by-step explanation, nobody pays attention to them anyway.

3 0
3 years ago
Help me solve for x. the angles they give to you are 138, 78, and 94. please help ​
Taya2010 [7]

Answer:

x = 8

Step-by-step explanation:

180 = 78 + 94 + x

180 =172 + x

-172 -172

18 = x

7 0
3 years ago
Please help !!!!!!!!!!!!
jekas [21]
This is for 2.X=22 so the total angle is 90° and you take away 68° and that leaves you with 22°
6 0
3 years ago
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