Answer:
II. One and only one solution
Step-by-step explanation:
Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.
Let assume the equation is given as;
x + 3y = 11 .... 1
x - y = -1 ....2
Using elimination method
Subtract equation 1 from 2
(x-x) + 3y-y = 11-(-1)
0+2y = 11+1
2y = 12
y = 12/2
y = 6
Substitute y = 6 into equation 2:
x-y = -1
x - 6 = -1
x = -1 + 6
x = 5
Hence the solution (x, y) is (5, 6)
<em>Hence we can say the equation has One and only one solution since we have just a value for x and y</em>
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Answer:
1. y = 9280 - 20x
2. f(y) = 6.37y - 3
Step-by-step explanation:
1. The equation is given to be
Now, rearranging the function we can write
⇒ y = 9280 - 20x
Hence, this is the equation as a function of x. (Answer)
2. The given function is y - 6.37x = - 3
Therefore, we can write, y = 6.37x - 3
Hence, f(x) = 6.37x - 3
⇒ f(y) = 6.37y - 3.
Hence, option D is true. (Answer)
Answer:
Nhjj
Step-by-step explanation:
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<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em><em> ❤️</em>
Answer:
(3, -3)
Step-by-step explanation:
Use the midpoint formula.
x = (x₁ + x₂) / 2
-1.5 = (-6 + x) / 2
-3 = -6 + x
x = 3
y = (y₁ + y₂) / 2
1 = (5 + y) / 2
2 = 5 + y
y = -3
The other endpoint is (3, -3).
Graph: desmos.com/calculator/aze920ns2h