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3 years ago

if a parabola has its vertex at (3,-5) and one of its x-intercepts at x=9, what is the other x-intercept?

Mathematics

1 answer:

Flauer [41]3 years ago

3 0

The other x intercept is

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Anyone wanna help???

OLEGan [10]

Answer:

its probably the first 1

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3 years ago

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Which equations are true?<br> Choose All Answers That Apply (10 Points)

Nataly [62]

Answer:

Step-by-step explanation:

Two negatives is a positive, and you want your outcome to be a positive x, therefore b is the correct answer.

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3 years ago

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A bin contains seven red chips, nine green chips, three yellow chips, and six blue chips. Find the probability of drawing a yell

igomit [66]

Answer:

a) 3/100

Step-by-step explanation:

There are 25 total chips

P(Yellow) = 3/25

With no replacement P(Blue) = 6/24 = 1/4

Multiply 3/25* 1/4= 3/100

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3 years ago

Matt is given a jar with eight marbles, six of which are red and two of which are green. Matt then randomly draws marbles withou

Ber [7]

Answer:

as a percentage it is: 0.25 x 0.2 =0.05 or 5%
but as a common fraction it is: 5/100 or 1/20

Step-by-step explanation:

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2 years ago

In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

Integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y):

$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

4 0

3 years ago