The ball takes approximately a time of 2.041 seconds to reach its maximum height.
<h3>What time does the ball take to reach maximum height?</h3>
The height of the ball as a function of time is modelled by a <em>quadratic</em> equation, the required information can be found by transforming the expression into <em>vertex</em> form:
h = - 4.9 · t² + 20 · t + 12
h = - 4.9 · (t² - 4.082 · t - 2.449)
h + (- 4.9) · (6.615) = - 4.9 · (t² - 4.082 · t + 4.166)
h - 32.414 = - 4.9 · (t - 2.041)²
The ball takes approximately a time of 2.041 seconds to reach its maximum height.
To learn more on quadratic equations: brainly.com/question/1863222
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Answer:
Step-by-step explanation:
Add subtract then divide
2) Add 0.1 to both sides. v/2.2=7.5
Then multiply by 2.2 on both sides.
v=16.5
4) Subtract 1.9 from both sides. -1.3g=-13
Divide both sides by -1.3
g=10
6) Add 1.4 to both sides. -12.9=-3d
Divide -3 on both sides.
d=4.3
Answer:
7
Step-by-step explanation:
$45- $8 = 37 (aka his raffle ticket spending money)
37÷5= 7, so the max # of raffle tickets he can buy is 7.
2.5 x 10 = 25 m^2
1.5 x 10 = 15 m^2
2 x 10 = 20 m^2
0.5 x 1.5 x 2 = 1.5 m^2 (2 times)
Total = 63 m^2
So just fill in 63.
