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Mkey [24]
2 years ago
8

The area of the parallelogram below is ____ square meters. A parallelogram with height labeled with 7 meters. The top horizontal

side is labeled 6 meters. The base of the left triangle formed by the height is 2 meters. Numerical Answers Expected
Mathematics
1 answer:
laiz [17]2 years ago
3 0

The area of the parallelogram in the image given is: 42 m².

<h3>What is the Area of a Parallelogram?</h3>

Area of a parallelogram = base × height

Given the parameters:

  • Base = 6 meters
  • Height = 7 meters

Area of the parallelogram = (6)(7)

Area of the parallelogram = 42 m²

Learn more about the area of parallelogram on:

brainly.com/question/3050890

#SPJ1

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Determine the number of bytes in 513 BM
Naddik [55]
We know, 
    1 MB = 1000 KB
513 MB = (1,000 * 513) KB
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Now,
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513,000 KB = (1,000 * 513,000) bytes
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∴ 513 MB is 513,000,000 bytes
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one gym membership charges $10 a month with a sign-up fee of $45. Another gym does not charge patrons a sign-up fee but costs $2
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Step-by-step explanation:

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1 year ago
A country has a total biocapacity of 6.21 ha/person, a biocapacity of grazing land of 0.85 ha/person, and a biocapacity of fores
leonid [27]

Answer:

44.8 %  

Step-by-step explanation:

Let p = the number of people. Then

Total biocapacity     = 6.21p  ha

Grazing biocapacity = 0.85p ha

Forest biocapacity    = <u>2.53p      </u>

Grazing + forest        = 2.78p ha

\text{Percent grazing + forest} = \dfrac{\text{grazing + forest}}{\text{Total}} \times 100 \, \% \\\\= \dfrac{\text{2.78p ha}}{\text{6.21p ha}} \times 100 \, \% = \mathbf{44.8 \,\%}

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2 years ago
I dunno, need help!
kodGreya [7K]
It is d,c,b im pretty sure
7 0
3 years ago
If (x-1)(x+5)=(x-h)^2+K then what is the value of h
vivado [14]
Solve for h:   (I'm using the completing the square)
(x - 1) (x + 5) = K + (x - h)^2
(x - 1) (x + 5) = K + (x - h)^2 is equivalent to K + (x - h)^2 = (x - 1) (x + 5):
K + (x - h)^2 = (x - 1) (x + 5)
Subtract K from both sides:
(x - h)^2 = (x - 1) (x + 5) - K
Take the square root of both sides:
x - h = sqrt((x - 1) (x + 5) - K) or x - h = -sqrt((x - 1) (x + 5) - K)
Subtract x from both sides:
-h = sqrt((x - 1) (x + 5) - K) - x or x - h = -sqrt((x - 1) (x + 5) - K)
Multiply both sides by -1:
h = x - sqrt((x - 1) (x + 5) - K) or x - h = -sqrt((x - 1) (x + 5) - K)
Subtract x from both sides:
h = x - sqrt((x - 1) (x + 5) - K) or -h = -x - sqrt((x - 1) (x + 5) - K)
Multiply both sides by -1:
Answer:  h = x - sqrt((x - 1) (x + 5) - K) or h = x + sqrt((x - 1) (x + 5) - K)


Solve for h: using the quadratic formula)
(x - 1) (x + 5) = K + (x - h)^2
(x - 1) (x + 5) = K + (x - h)^2 is equivalent to K + (x - h)^2 = (x - 1) (x + 5):
K + (x - h)^2 = (x - 1) (x + 5)
Expand out terms of the left hand side:
h^2 + K - 2 h x + x^2 = (x - 1) (x + 5)
Subtract (x - 1) (x + 5) from both sides:
h^2 + K - 2 h x + x^2 - (x - 1) (x + 5) = 0
h = (2 x ± sqrt(4 x^2 - 4 (K + x^2 - (x - 1) (x + 5))))/2:
<span>Answer:  h = x + sqrt(-5 - K + 4 x + x^2) or h = x - sqrt(-5 - K + 4 x + x^2)</span>
7 0
2 years ago
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