Answer:
wats part A?
Step-by-step explanation:
Give me the data:)
Answer:
216
Step-by-step explanation:
Hope this helps.
y² - 4y - 2x - 4 = 0
<u> +2x +4 </u> <u>+2x + 4 </u>
y² - 4y = 2x + 4
<u> +4 </u> <u> +4 </u>
(y - 2)² = 2x + 8
<u> -8 </u> <u> -8 </u>
(y - 2)² - 8 = 2x
(y - 2)² - 4 = x
x = (y - 2)² - 4
<em>Note: this is a parabola whose axis of symmetry is y = 2 and vertex is (-4, 2)</em>
To find the average velocity in a velocity-time graph at a particular interval, simply determine the gradient at that particular interval.
<span>a. average velocity= 4/1 </span>
<span>= 4m/s </span>
<span>b. average velocity from 1 to 2.5s= 6/(2.5-1) </span>
<span>= 4m/s </span>
<span>average velocity from 2.5 to 4.0s= 0m/s </span>
<span>average velocity from 0 to 4.0s= (4+0)/4 </span>
<span>= 1m/s </span>
<span>c. average velocity from 1.0 to 4.0s= (4/3)m/s </span>
<span>average velocity from 4.0 to 5.0s= 2/1 </span>
<span>= 2.0m/s </span>
<span>average velocity from 1.0 to 5.0s= ((4/3)+2)/4 </span>
<span>= (5/6)m/s </span>
<span>d. average velocity from 0 to 4.0s= 1.0m/s </span>
<span>average velocity from 4.0 to 5.0s= 2.0m/s </span>
<span>average velocity from 0 to 5.0s= (1.0+2.0)/5 </span>
<span>= (3/5)m/s </span>
