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2 years ago

11

Pls help me whats the slope

1 answer:

blsea [12.9K]2 years ago

6 0

Answer: it looks like its gonna be a decimal but it looks like its gonna be

-7/8.5

Step-by-step explanation:

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What is the units digit of 2 to the 50th power

11111nata11111 [884]

Notice that

$2^1=2$
$2^2=4$
$2^3=8$
$2^4=16$
$2^5=32$

so that for each power of 2, there is a pattern of period 4. This means that for integers $k\ge0$ , each of $2^{4k}$ , $2^{4k+1}$ , $2^{4k+2}$ , and $2^{4k+3}$ have the same units digit.

We can write $50=4(12)+2$ , and since $3=4(0)+2$ , it follows that $2^{50}$ and $2^3$ share the same units digits. So the units digit of $2^{54}$ is 8.

6 0

2 years ago

Nicole bought a mattress priced at $938. Shipping and handling cost an additional 27% of the price. What was the total cost of t

larisa [96]

938.00 + 27%= 1191.26

3 0

2 years ago

Read 2 more answers

ANSWER AND EXPLAIN PLEASE ILL MARK BRAINLIEST!!!!!!!!!!!

motikmotik

Answer:

x = 1 and y = -2

Step-by-step explanation:

Given that,

2x-3y = 8 ..(1)

4x+3y = -2 ..(2)

Add equation (1) and (2),

2x-3y+4x+3y = 8+(-2)

6x = 6

x = 1

Put the value of x in equation (1).

2-3y = 8

2-8 = 3y

-6 = 3y

y = -2

Hence, the value of x is 1 and that of y is -2.

3 0

2 years ago

Which two values of x are roots of the polynomial below? x^2-3x+5

Gemiola [76]

Given:

Polynomial $x^2-3x+5$

To find:

The values of x.

Solution:

$x^2-3x+5=0$

Quadratic equation formula:

$$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here $a=1, b=-3, c=5$ .

Substitute the values in the formula, we get

$$x=\frac{-(-3) \pm \sqrt{(-3)^{2}-4 \cdot 1 \cdot 5}}{2 \cdot 1}$

$$x=\frac{3 \pm \sqrt{9-20}}{2}$

$$x=\frac{3 \pm \sqrt{-11}}{2}$

$$x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}$

Option E and option F are the roots of the polynomial.

The values of x are $x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}$ .

7 0

2 years ago

John is skiing on a mountain with an altitude of 1200 feet. The angle of depression is 21 About how far does

Agata [3.3K]

Answer:

John ski down the mountain is 1285.37 feet.

Step-by-step explanation:

Given : John is skiing on a mountain with an altitude of 1200 feet. The angle of depression is 21.

To find : About how far does John ski down the mountain ?

Solution :

We draw a rough image of the question for easier understanding.

Refer the attached figure below.

According to question,

Let AB be the height of mountain i.e. AB=1200 feet

The angle of depression is 21 i.e. $\theta=21^\circ$

We have to find how far does John ski down the mountain i.e. AC = ?

Using trigonometric,

$\cos\theta = \frac{AB}{AC}$

$\cos(21)= \frac{1200}{AC}$

$AC=\frac{1200}{\cos(21)}$

$AC=1285.37$

Therefore, John ski down the mountain is 1285.37 feet.

7 0

3 years ago