P = $70, p = 2.5% = 0.025
q = 1 + 0.025 / 12 = 1.002
Future value of a periodic deposit:
A = P · q · ( q^30 - 1 ) / ( q - 1 )
A = 70 · 1.002 · ( 1.002^30 - 1 ) / ( 1.002 - 1 )
A = $2,166
Answer:
He will have $2.166 in 30 months.
Answer:
48
Step-by-step explanation:
So your equation is: 5y3 - 21 + 6y2 + (25 ÷ 5) and y = 2.
Evaluate for y=2
5(23)−21+6(22)+
25
5
5(23)−21+6(22)+
25
5
=48.
So the answer is 48.
Answer: old McDonald has 54 chickens and 2 cows.
Step-by-step explanation:
Let x represent the number of chickens that old McDonald have.
Let y represent the number of cows that old McDonald have.
He counted 56 heads. A chicken and a cow has one head each. It means that
x + y = 56
He counted 116 legs. A chicken has 2 legs and a cow has 4 legs. It means that
2x + 4y = 116 - - - - - - - - -1
Substituting x = 56 - y into equation 1, it becomes
2(56 - y) + 4y = 116
112 - 2y + 4y = 116
- 2y + 4y = 116 - 112
2y = 4
y = 4/2 = 2
x = 56 - y = 56 - 2
x = 54
X| 2|4|6jsososodidididjfjfifififififofioff
It would be: $60.00 - ($46.42+$21.05)
$60.00 - $67.47 = -$7.47
