Answer:
For maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.
Step-by-step explanation:
Let the length of the rectangular exercise run = l ft
and width of the run = w ft
Sinoman has to cover a rectangular exercise run from three sides with the fencing material,
So length of the material = (l + 2w) ft
l + 2w = 100
l = 100 - 2w --------(1)
Area of the rectangular area covered = Length × width
A = lw
A = w(100 - 2w) [(l = 100 - 2w)from equation (1)
For maximum area we find the derivative of area and equate it to zero.
![\frac{dA}{dw}=\frac{d}{dw}[w(100-2w)]](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdw%7D%3D%5Cfrac%7Bd%7D%7Bdw%7D%5Bw%28100-2w%29%5D)

A' = 100 - 4w
For A' = 0
100 - 4w = 0
4w = 100
w = 25 ft
From equation (1)
l = 100 - 2w
l = 100 - 2×(25)
l = 50 ft
Therefore, for maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.
Answer:
Standard: 0.712
Expanded: 0.7 + 0.01 + 0.002
Step-by-step explanation:
Seven hundred twelve thousandths
.tenths,hundredths,thousandths
0.712
Every number in expanded fits in its place.
0.712
^ ^ ^
0.7 0.01 0.002
Answer:
x = 1+√3 i/2 and x = 1-√3 i/2
Step-by-step explanation:
Given the expression x^2 - x+ 1, we are to factorize the expression as shown;
x^2 - x+ 1,
using the general formula
x = -(-1)±√1²-4(1)/2(1)
x = 1±√1-4/2
x= 1±√-3/2
x = 1±√3 i/2
Hence the required value of x are x = 1+√3 i/2 and x = 1-√3 i/2
Answer:
the answer is Dilations preserve betweenness of points; therefore, the corresponding sides of pentagons G and G′ are proportional.
Step-by-step explanation:
i took the test and got it right