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3 years ago

Find the value of the variable.

Mathematics

1 answer:

Bezzdna [24]3 years ago

8 0

X= 4. You get this by setting the two equations equal to each other and isolating the variable and the constant.

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Please help. I need a step by step explanation. Extra points will be given as well as brainiest!!!

Shalnov [3]

Answer:

V =113.04

Step-by-step explanation:

A sphere has a surface area of 113.04

SA = 4 pi r^2

113.04 = 4 pi r^2

Let pi 3.14

113.04 = 4 *(3.14) r^2

113.04 = 12.56 r^2

Divide each side by 12.56

113.04/12.56 = r^2

9 = r^2

Take the square root of each side

3 =r

We want to find the volume

V = 4/3 pi r^3

V = 4/3 (3.14) 3^3

V =113.04

3 0

3 years ago

Math help please please

Vika [28.1K]

Answer:

3(3x+1) (2x-1)

Step-by-step explanation:

18x^2 -3x-3

Factor out a 3

3(6x^2 -x-1)

3(3x+1) (2x-1)

6 0

3 years ago

Select the least common multiple of 12 and 15. A. 3 B. 15 C. 60 D. 180

ad-work [718]

Answer:

Step-by-step explanation:

12=2⋅2⋅3

15=3⋅5

We see that they both share 3 is their LCM.

We divide each number by their LCM.

123⇒4

153⇒5

We multiply these two quotients and the LCM to get our final answer:

3⋅4⋅5=60

That is our answer!

Hope this helped! :)

7 0

3 years ago

172+(-167)+(-10)+(-144) what's the sum

Pepsi [2]

-149 would be your answer

6 0

3 years ago

A water storage tank has the shape of a cylinder with diameter 14 ft. It is mounted so that the circular cross-sections are vert

andrezito [222]

Answer:

percentage of the total capacity is 75.6%

Step-by-step explanation:

Hello! To solve this problem we follow the following steps

1. draw the complete scheme of the problem (see attached image)

2. To solve this problem we must find the area of the circular sector using the following equation.(c in the second attached image)

$A=\frac{R^2}{2} (\alpha -sin\alpha )$

$\alpha =2arccos(\frac{d}{R})$

3. observing the attached images we replace the values in the equations and find the area of the circular sector, remember that you must transform the angle to radians

$\alpha =2arccos(\frac{5}{7})=88.83$

$A=\frac{R^2}{2} (\alpha -sin\alpha )\\A=\frac{7^2}{2} (88.83-sen88.83)*\frac{\pi rad}{180} =37.57ft^2$

4.we calculate the area of the total circle (At), then subtract the area of the circular sector (Ac) to find the area occupied by water (Aw)

$At=\frac{\pi }{4} (14ft)^2=153.93ft^2$

Aw=At-Ac=153.93-37.57=116.36ft^2

5.Finally, we calculate the percentage that represents the water in the tank by dividing the area of the water over the total area of the tank

$\frac{116.36}{153.93} *100=75.6$

percentage of the total capacity is 75.6%

3 0

3 years ago