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romanna [79]
3 years ago
12

Find the value of the variable.

Mathematics
1 answer:
Bezzdna [24]3 years ago
8 0
X= 4. You get this by setting the two equations equal to each other and isolating the variable and the constant.
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What are the coordinates of the vertex for f(x) = 3x2 + 6x + 3? (−1, 0) (3, 6) (0, −1) (6, 3)
larisa [96]

Answer:

The vertex is the point (-1,0)

Step-by-step explanation:

we have

f(x)=3x^{2} +6x+3

we know ow that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

Convert the equation into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)-3=3x^{2} +6x

Factor the leading coefficient

f(x)-3=3(x^{2} +2x)

Complete the square. Remember to balance the equation by adding the same constants to each side

f(x)-3+3=3(x^{2} +2x+1)

f(x)=3(x^{2} +2x+1)

Rewrite as perfect squares

f(x)=3(x+1)^{2}

therefore

the vertex is the point (-1,0)

6 0
3 years ago
Read 2 more answers
Consider the following data set with an even number of data
photoshop1234 [79]
I guess “1” is the minimum value
8 0
2 years ago
Jana is training for a triathlon. If Jana biked at a constant rate, how many miles did she bike in the first 15 minutes?
Harman [31]

In order to answer, I would first need to know Jana's speed, not that she biked at a constant rate.

7 0
3 years ago
F (x)<br> 15x + 13 Which is the average rate of change over for the interval 0 &lt; x &lt; 10?
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3 years ago
Can someone complete the square
pshichka [43]
To do these, start by looking at the "b" value -6.
divide it by 2

-6/2 = -3

now square this number

(-3)^2 = 9

this is what you need for the "c" value

there is only a 5 for the c value so add 4 to both sides of the equation. ( +4 = +4)

y +4 = x^2 -6x +5 +4
y +4 = x^2 -6x +9
y +4 = (x -3)^2
y = (x -3)^2 - 4

vertex ( 3, -4) upwards facing like a bowl, because the "a" value is positive. So the vertex is the minimum, lowest point on the graph.


7 0
3 years ago
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