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LiRa [457]
3 years ago
9

Select all the possible names for the following angle

Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

The answers are options d and e

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Jared and Zach are practicing their free throws. Jared attempted x shots and made 75% of them. Zach attempted 10 more shots than
leonid [27]

0.75x+0.8(x + 10) = 101

4 0
3 years ago
Traffic flow at 1st Ave and High St is twice the traffic flow at 2nd ave and central. Compare the graph of the traffic flow at 1
Anna007 [38]

Answer:

The period of the graph of the traffic flow at 1st Ave and High St is half as long as the period of the graph of the traffic flow at 2nd Ave and Central.

Step-by-step explanation:

3 0
2 years ago
The following system of equations is graphed below.
navik [9.2K]
One way is subsitute
I like solving

so

what you do is this
add the equaitons to gether to eliminate x

2y=x+5
<u>3y=-x-3 +</u>
5y=0x+2
5y=2
y=2/5

sub back


2y=x+5
2(2/5)=x+5
4/5=x+5
minus 5
4/5-25/5=x
-21/5=x

the point is (x,y) or
(-21/5,2/5)
aprox
(-4.2,0.4)
I think they wanted you to read the garph you should have attached and guess the answer
the closes one is
hmm, x=-3
and y=1

so then D is the answer

3 0
3 years ago
Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis
Lesechka [4]

Answer:

The limit of the function does not exists.

Step-by-step explanation:

From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.

For x<2

f(x)=6

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.

For x>2

f(x)=-3

The value of y is 1 at x=2, because of he close circles on (2,1).

For x=2

f(x)=1

Therefore the graph represents a piecewise function, which is defined as

f(x)=\begin{cases}6& \text{ if } x2 \end{cases}

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

lim_{x\rightarrow a^-}f(x)=lim_{x\rightarrow a^+}f(x)

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.

lim_{x\rightarrow 2^-}f(x)=6

lim_{x\rightarrow 2^+}f(x)=-3

6\neq-3

Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.

6 0
3 years ago
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An robot takes 8 minutes to pack 6,000 boxes.What is the robot's rate <br><br>i think 750?
IgorLugansk [536]

Answer:

you are correct :D

Step-by-step explanation:

6 0
4 years ago
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