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sveticcg [70]
3 years ago
13

Suppose the integral from 2 to 8 of g of x, dx equals 12, and the integral from 6 to 8 of g of x, dx equals negative 3, find the

value of 2 times the integral from 2 to 6 of g of x, dx .
7.5
15
18
30
Mathematics
1 answer:
Artyom0805 [142]3 years ago
8 0

\displaystyle\int_2^8g(x)\,\mathrm dx=12

\displaystyle\int_6^8g(x)\,\mathrm dx=-3

Use the fact that integrals are additive on their intervals. Mathematically, if c\in[a,b], then

\displaystyle\int_a^bg(x)\,\mathrm dx=\int_a^cg(x)\,\mathrm dx+\int_c^bg(x)\,\mathrm dx

So we have

\displaystyle2\int_2^6g(x)\,\mathrm dx=2\left(\int_2^8g(x)\,\mathrm dx-\int_6^8g(x)\,\mathrm dx\right)=2(12-(-3))=30

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Solve : x + 1/2 + x + 2/3 − x + 3/4 = 2
valentinak56 [21]

Answer:

x= 1 7/12

Step-by-step explanation:

x+1/2+x+2/3-x+3/4=2

1. We know that x+x-x=x

2. 1/2+2/3-3/4=6/12+8/12-9/12=5/12

3. x+5/12=2

4. x=2-5/12

x=1 7/12

8 0
3 years ago
Read 2 more answers
I am a number greater than 40,000 and less than 60,000. My ones digit and tens digit are the same. My ten-thousands digit is 1 l
jarptica [38.1K]
I am a number greater than 40,000 and less than 60,000:

40,000 < n < 60,000

This means that:

n = 10,000n₁ + 1,000n₂ + 100n₃ + 11n₄

And also:

4 ≤ n₁ < 6

0 ≤ n₂ ≤ 9

0 ≤ n₃ ≤ 9

0 ≤ n₄ ≤ 9

My ten thousands digit is 1 less than 3 times the sum of my ones digit and tens digit:

n₁ = 3*2n₄ - 1

n₁ = 6n₄ - 1

This means that:

n = 10,000*(6n₄-1) + 1,000n₂ + 100n₃ + 11n₄

n = 60,000n₄ - 10,000 + 1,000n₂ + 100n₃ + 11n₄

n = 60,011n₄ - 10,000 + 1,000n₂ + 100n₃

<span>My thousands digit is half my hundreds digit, and the sum of those two digits is 9:

n</span>₂ = 1/2 * n₃
<span>
n</span>₂ + n₃ = 9
<span>
Therefore:

n</span>₂ = 9 - n₃
<span>
Therefore:

9 - n</span>₃ = 1/2 * n₃
<span>
9 = 1/2 * n</span>₃ + n₃
<span>
9 = 1.5 * n</span>₃
<span>
Therefore:

n</span>₃ = 6
<span>
If n</span>₃=6, n₂=3.
<span>
This means that:

</span>n = 60,011n₄ - 10,000 + 1,000*3 + 100*6

n = 60,011n₄ - 10,000 + 3,000 + 600

n = 60,011n₄ - 6,400

Therefore:

0<n₄<2, so n₄=1.

If n₄=1:

n = 60,011 - 6,400

n = 53,611

Answer:

53,611
3 0
3 years ago
If G = {(-1, 7),(-8, 2),(0, 0),(6, 6)), then the range of G is
lakkis [162]

Answer:

B) {-8,-1,0,6)

Step-by-step explanation:

range is always y

4 0
3 years ago
Consider two forces of 17 and 42 pounds both acting in the horizontal direction on a single object. find the resultant force act
lys-0071 [83]

The forces have a magnitude of 59 pounds, and their direction angles are zero.

<h3>What is the magnitude of force?</h3>
  • The total amount of forces exerted on an object is referred to as the magnitude of force. The strength of the force increases when all the forces are pulling in the same direction. The force's strength reduces when forces are exerted on an item from different angles.
  • When two forces operating on a body in opposite directions along the same line of action are equal in magnitude, they cancel one another out. When two forces operating on a body in opposite directions along the same line of action are equal in magnitude, they cancel one another out.
  • According to this formula, the amount of net force acting on an item is equal to the mass times the acceleration of the object.
  • Magnitude is a term that refers to size or importance. The depth of the Grand Canyon serves as an illustration of magnitude. The scope of the hunger crisis in the world serves as an illustration of magnitude. A measurement of the energy released by an earthquake, as shown on the Richter scale (geology).

Two forces of 17 and 42 pounds act horizontally on an object.

i.e

F1 = 17 pounds

F2 = 42 pounds

As the magnitude of the force represents the sum of all the forces

The direction is the same

Magnitude : 17 + 42 = 59 pounds

The Direction angles : 0

As they have the same direction so angle will be 0.

The forces have a magnitude of 59 pounds, and their direction angles are zero.

To learn more about the Magnitude of forces and Direction angles of forces, refer to:

brainly.com/question/14584426

#SPJ4

7 0
2 years ago
What is the answer to the question
Minchanka [31]
D'
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3 0
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