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SOVA2 [1]
3 years ago
6

X^6+3x^3-5 write the expression in quadratic form

Mathematics
1 answer:
Art [367]3 years ago
3 0

Step-by-step explanation:

v =  {x}^{3}  \\  {v}^{2}  + 3v - 5 = 0 \\

Solving this equation using the quadratic formula, we get two real solutions :

1.1926 or -4.1926

Now we know the values of v , we can calculate x since x is ∛ v

{x}^{6}  + 3 {x}^{3}  - 5 = 0

x =  \sqrt[3]{1.1926}  = 1.0605 \\ x =  \sqrt[3]{ - 4.1926}  =  - 1.6125

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Please help me it's urgent!
Crank

Answer:

y = 2x-5

y=-x+4

Step-by-step explanation:

Just need to solve the:

x+y=4

y-2x=-5

And we have:

x=3

y=1

Then replace x and y into the answer to find the correct one

7 0
3 years ago
A total of 1,650 boxes of Girl Scout cookies were sold last week. Each large box cost $3.50 and each small box cost $2.00. The G
s344n2d4d5 [400]

Answer:

900 large boxes were sold, and 750 small boxes.

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

x is the number of large boxes of cookies sold.

y is the number of small boxes of cookies sold.

A total of 1,650 boxes of Girl Scout cookies were sold last week.

This means that

x + y = 1650

So

x = 1650 - y

Each large box cost $3.50 and each small box cost $2.00. The Girl Scout group earned $4,650.

This means that

3.5x + 2y = 4650

Since x = 1650 - y

3.5(1650 - y) + 2y = 4650

5775 - 3.5y + 2y = 4650

1.5y = 1125

y = \frac{1125}{1.5}

y = 750

x = 1650 - y = 1650 - 750 = 900

900 large boxes were sold, and 750 small boxes.

8 0
3 years ago
The distribution of SAT scores of all college-bound seniors taking the SAT in 2014 was approximately normal with a mean of 14971
RideAnS [48]

Answer:

P(X<1200) is 0.8212

Step-by-step explanation:

Test statistic (z) = (X - mean)/sd

X is score of a tester = 1200

mean = 1497

sd = 322

z = (1200 - 1497)/322 = -297/322 = -0.92

The cumulative area of the test statistic is the probability that X<1200. The cumulative area is 0.8212.

Therefore, P(X<1200) = 0.8212

8 0
3 years ago
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