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SOVA2 [1]
3 years ago
6

X^6+3x^3-5 write the expression in quadratic form

Mathematics
1 answer:
Art [367]3 years ago
3 0

Step-by-step explanation:

v =  {x}^{3}  \\  {v}^{2}  + 3v - 5 = 0 \\

Solving this equation using the quadratic formula, we get two real solutions :

1.1926 or -4.1926

Now we know the values of v , we can calculate x since x is ∛ v

{x}^{6}  + 3 {x}^{3}  - 5 = 0

x =  \sqrt[3]{1.1926}  = 1.0605 \\ x =  \sqrt[3]{ - 4.1926}  =  - 1.6125

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What is the approximate area of the unshaded region under the standard normal curve below? Use the portion of the standard norma
Harlamova29_29 [7]

The approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.

It is given that the standard normal curve shows the shaded area in the curve.

It is required to find the approximate area of the unshaded region under the standard normal curve.

<h3>What is a normal distribution?</h3>

It is defined as the continuous distribution probability curve which is most likely symmetric around the mean. At Z=0, the probability is 50-50% on the Z curve. It is also called a bell-shaped curve.

In the curve showing the shaded region area between:

\rm P(1 < Z < 2)

First, we calculate the shaded region area:

From the data given the value of Ф(1) = 0.8413.

P(Z<1)  = 0.8413  and

P(Z<2) =  0.9772

The area of the shaded region:

= P(Z<2) - P(Z<1)

=  0.9772 - 0.8413

= 0.1359

The area of the unshaded region:

= 1 - The area of the shaded region  ( because the curve is symmetric)

= 1 - 0.1359

= 0.8641 ≈ 0.86

Thus, the approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.

Know more about the normal distribution here:

brainly.com/question/12421652

4 0
2 years ago
What’s 43 rounded to the nearest 10!???!
Lilit [14]

Answer:

40.

  • Which is 43 closer to? 40 or 50?
  • 43 is closer to <em>40.</em>

<em>I hope this helped at all.</em>

5 0
3 years ago
Read 2 more answers
If A(-5,7), B(-4,-5), C(-1,-6) and D(4,5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD.
MrMuchimi
After plotting the quadrilateral in a Cartesian plane, you can see that it is not a particular quadrilateral. Hence, you need to divide it into two triangles. Let's take ABC and ADC.

The area of a triangle with vertices known is  given by the matrix
M = \left[\begin{array}{ccc} x_{1}&y_{1}&1\\x_{2}&y_{2}&1\\x_{3}&y_{3}&1\end{array}\right]

Area = 1/2· | det(M) |
        = 1/2· | x₁·y₂ - x₂·y₁ + x₂·y₃ - x₃·y₂ + x₃·y₁ - x₁·y₃ |
        = 1/2· | x₁·(y₂ - y₃) + x₂·(y₃ - y₁) + x₃·(y₁ - y₂) |

Therefore, the area of ABC will be:
A(ABC) = 1/2· | (-5)·(-5 - (-6)) + (-4)·(-6 - 7) + (-1)·(7 - (-5)) |
             = 1/2· | -5·(1) - 4·(-13) - 1·(12) |
             = 1/2 | 35 |
             = 35/2

Similarly, the area of ADC will be:
A(ABC) = 1/2· | (-5)·(5 - (-6)) + (4)·(-6 - 7) + (-1)·(7 - 5) |
             = 1/2· | -5·(11) + 4·(-13) - 1·(2) |
             = 1/2 | -109 |
<span>             = 109/2</span>

The total area of the quadrilateral will be the sum of the areas of the two triangles:

A(ABCD) = A(ABC) + A(ADC) 
               = 35/2 + 109/2
               = 72
8 0
4 years ago
Which is the best first step and explanation for solving this system of equations? 3x+4y=12 3x=2y-8​
Greeley [361]

Answer:

Since it is a simultaneous equation,

Using elimination method, Multiply equation 1 by the co efficient of x in equation 2 and multiply equation 2 by the co efficient of x in equation 1.

Step-by-step explanation:

For further explanation , Please contact me through the comment section.

:)

6 0
3 years ago
5
pychu [463]

Answer:

B 8.56

this is the answer because you simply add what he bought so 1.13+1.13+1.76 which is 4.02 then subtract what he started with which was 12.58 so 12.58-4.02 is 8.56 so that's your answer

8 0
2 years ago
Read 2 more answers
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