Question:
If a sample of 2 hammer is selected
(a) find the probability that all in the sample are defective.
(b) find the probability that none in the sample are defective.
Answer:
a 
b 
Step-by-step explanation:
Given
--- hammers
--- selection
This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities
Solving (a): Probability that both selection are defective.
For two selections, the probability that all are defective is:
Solving (b): Probability that none are defective.
The probability that a selection is not defective is:
For two selections, the probability that all are not defective is:
Answer:
2d-5=Q ?
Step-by-step explanation:
Am I supposed to be representing quarters too? I think this should solve it though. Lmk if somethings wrong :)
Calculate the mean, median, and mode for the set 7, 9, 8, 8, 10, 9, 8, 7, 8, 6, 9, 5, 6, 8, 9, 7, 7, 8, 10, 8 please answer asap
tatiyna
Step-by-step explanation:
Mean (Average):7.89474. Median (Middle):8. Mode (Most Common):8
He first two are relatively easy. f(x-2) shifts it sideways (2 to the right in this case) f(x) -2 shifts it straight down (by 2)
f(2x) means replace x with 2x in the original 4(2x + 1)^2 − 3 if you factor out the 2 from the square root you get 4*sqr(2) ( x + ½)^2 - 3 which is now in the form a ( x -h)^2 + k the vertex is now at (-½, -3) (it used to be at (-1,-3) the "a" has gotten bigger, which makes the parabola "skinnier" (it goes up faster)
2•f(x) becomes 2*( 4(x + 1)2 − 3 ) = 8 (x+1)^2 -6 where is the vertex now? is this parabola fatter or skinnier than the original f(x) ?
(3, - 2)
given y = - 2, then
- 2x + 4 = - 2 ( solve for x )
subtract 4 from both sides
- 2x = - 6 ( divide both sides by - 2 )
x = 
= 3
