The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
The answer is 19 hours. I divided 516 by 26 and the result was 19.84 but i only took 19 which multiplied by 26 gives me 494 & if you add 22 it gives you 516. You're welcome.
On three does it tells you the data
372 simplified is: 2*2*3*31. Thus, 372*7= 2*2*3*31*7. I believe that's what the question is asking for, Hope that helps. :)
Answer:
The answer is A
Step-by-step explanation:
Traingle ABC is congruent to traingle EFD by hl rule
