Answer:
a
Step-by-step explanation:
3-5 is -2
10 800 0 to the first problem
I'm assuming you're looking for the dimensions of the plot. I'm going with that. ;) If the length of the plot is 5 meters longer than the width, then L = w + 5. The area for a rectangle is L*w, and we have an area value of 20,000 so our formula is 20000=(w+5)(w) and

. We will bring the 20,000 over by subtraction and set the polynomial equal to 0 to factor and solve for w.

Solving for w we get values of w=138.9 and -143.9. Of course the 2 things in math that will never EVER be negative are time and distance/length, so -143.9 is out. Our width is 138.9 and the length is 138.9 + 5 so the length is 143.9. And there you go! Hope that's what you needed!
Answer:
The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for the average using the finite correction factor is:

The information provided is:

The critical value of <em>z</em> for 95% confidence level is,
<em>z</em> = 1.96
Compute the 95% confidence interval for the average number of years until the first major repair as follows:


Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).
Answer:
Number of smaller ropes she can make from the larger rope = 2/3
Step-by-step explanation:
Total length of rope = 2/5 ft
Length of smaller rope = 3/5 ft
How many smaller ropes can she make from the larger rope?
Number of smaller ropes she can make from the larger rope = Total length of rope / Length of smaller rope
= 2/5 ÷ 3/5
= 2/5 × 5/3
= (2*5)/(5*3)
= 10/15
= 2/3
Number of smaller ropes she can make from the larger rope = 2/3