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2 years ago

most americans supported the fight for independence in latin america because it reminded then of the what?

SAT

1 answer:

meriva2 years ago

3 0

Answer:

They were inspired by the example of the US

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If f(x)=2x+1 and g(x)=x^2+7, which of the following is equal to f(g(x))

topjm [15]

Answer: $2x^{2} +15$

Explanation:

so basically f(g(x)) is telling you to plug the entire g(x) equation into x in the f(x) equation so it will look like this

2( $x^{2} +7$ ) + 1

and then simplify

$2x^{2} +14 + 1$

$2x^{2} +15$

7 0

3 years ago

Read 2 more answers

Plz help fast!!!!!!!!!!!!!!!!!!!!!

Montano1993 [528]

The answer should be A because the 2 is a negative 2 not a positive 2.

7 0

2 years ago

Read 2 more answers

A spring with a spring constant of 150 n/m has an equilibrium length of 8. 0 cm. What is the change in spring potential energy w

natima [27]

When the spring is stretched to 11.0 cm - 8.0 cm = 3.0 cm = 0.030 m away from equilibrium, it stores

1/2 (150 N/m) (0.030 m)² = 0.0675 J

of potential energy, while stretching it to 14.0 cm - 8.0 cm = 6.0 cm = 0.060 m from equilibrium stores

1/2 (150 N/m) (0.060 m)² = 0.27 J

Then the change in potential energy is 0.27 J - 0.0675 J = 0.2025 J ≈ 0.21 J

8 0

2 years ago

After approximately what y-value does the exponential function surpass the quadratic function?

Harrizon [31]

Answer:

I believe the answer you are looking for is 80.

Explanation:

6 0

2 years ago

B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of len

Citrus2011 [14]

Answer:

The additional words is $2^n$

Explanation:

Given

$B(n) = 2^n$

Required

Determine the additional words; i.e. $B(n + 1) - B(n)$

From the given parameters, we have that;

B is a function of n

Such that;

$B(n) = 2^n$

To calculate $B(n+1)$ , we simply substitute n + 1 for n

$B(n) = 2^n$

$B(n + 1) = 2^{n + 1}$

Applying laws of indices

$B(n + 1) = 2^{n} * 2^1$

$B(n + 1) = 2^{n} * 2$

$B(n + 1) = 2(2^{n})$

Calculating Additional Binary Code;

$B(n + 1) - B(n)$

Substitute values for B(n + 1) and B(n)

$B(n + 1) - B(n) = 2(2^n) - 2^n$

Express $2^n$ as $2^ n * 1$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 1$

Express 1 as $2^0$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0$

Factorize

$B(n + 1) - B(n) = 2^n(2 - 2^0)$

$B(n + 1) - B(n) = 2^n(2 - 1)$

$B(n + 1) - B(n) = 2^n(1)$

$B(n + 1) - B(n) = 2^n$

Hence, the additional words is $2^n$

8 0

3 years ago