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SIZIF [17.4K]
3 years ago
5

There's an App for That!

Computers and Technology
1 answer:
AleksandrR [38]3 years ago
6 0

Answer:

Im confused man

Explanation:

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897,100 rounded to the nearest hundred thousand is
dmitriy555 [2]

The answer would be 900,100 because the hundred thousand is the 8 and since the number next to the 8 is a nine, the 8 is rounded up

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How much does 1 American tank cost on gas for a regular mission? Depending on your answer, I will give you the right amount of p
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Most of the cars or other vehicles in the United States regularly have tanks that can hold up to 12 gallons worth of gas. The price of gas in not consistent. Sometimes prices are high and sometimes prices are low. Just like to day the price of a gallon is worth $2.2. But in an average, gas costs $3.8 per gallons. Therefore, on a regular basis a standard American which can hold 12 gallons costs $46.2.
5 0
3 years ago
OSHA standards appear in the ___________ and are then broken down into ____________.
Alisiya [41]
OSHA standards appear in the Code of Federal Regulations (CFR) <span>and was then broken down into two parts. It contains standards to ensure a </span>
4 0
3 years ago
Write a function shampoo_instructions() with parameter num_cycles. If num_cycles is less than 1, print "Too few.". If more than
EastWind [94]

Answer:

Following are the code to the given question:

def shampoo_instructions(num_cycles):#defining a method shampoo_instructions that accepts num_cycles as a parameter

   if num_cycles < 1:#defining an if block that num_cycles value is less than 1

       print('Too few.')#print message  

   elif num_cycles > 4:#defining elif block that checks num_cycles is greater than 4

       print('Too many.')#print message  

   else:#defining else block

       N= 1;#defining N variable that holds a value 1

       for N in range(N, num_cycles+1):#defining for loop that check value in range

           print(N , ": Lather and rinse.")#print message  

       print('Done.')#print message  

shampoo_instructions(2)#calling the method

Output:

1 : Lather and rinse.

2 : Lather and rinse.

Done.

Explanation:

In this code, a method "shampoo_instructions" is defined, that accepts a variable "num_cycles" in its parameter, and in the next step, the multiple conditional statements have used that check the "num_cycles" values which can be defined as follows:

  • The if the block checks the parameter value is less than 1, and it prints the value as the message.
  • In the next step, the elif block is used that checks parameter value is greater than 4, and it prints the value as the message.
  • In the else block, it uses the for loop that checks the value in the range and prints its value and calling the method.
6 0
3 years ago
6.25 (Prime Numbers) A positive integer is prime if it’s divisible by only 1 and itself. For example, 2, 3, 5 and 7 are prime, b
faltersainse [42]

Answer:

  1. public class Main {
  2.    public static void main (String [] args) {
  3.        for(int i = 2; i < 10000; i++){
  4.            if(isPrime1(i)){
  5.               System.out.print(i + " ");
  6.            }
  7.        }
  8.        System.out.println();
  9.        for(int i = 2; i < 10000; i++){
  10.            if(isPrime2(i)){
  11.                System.out.print(i + " ");
  12.            }
  13.        }
  14.    }
  15.    public static boolean isPrime1(int n){
  16.      
  17.        for(int i=2; i <= n/2; i++){
  18.            if(n % i  == 0){
  19.                return false;
  20.            }
  21.        }
  22.        return true;
  23.    }
  24.    public static boolean isPrime2(int n){
  25.        for(int i=2; i <= Math.sqrt(n); i++){
  26.            if(n % i  == 0){
  27.                return false;
  28.            }
  29.        }
  30.        return true;
  31.    }
  32. }

<u></u>

Explanation:

Firstly, create the first version of method to identify a prime number, isPrime1. This version set the limit of the for loop as n/2. The for loop will iterate through the number from 2 till input n / 2 and check if n is divisible by current value of i. If so, return false to show this is not a prime number (Line 22 - 26). Otherwise it return true to indicate this is a prime number.

In the main program, we call the isPrime1 method by passing the i-index value as an argument within a for-loop that will iterate through the number 2 - 10000 (exclusive).  If the method return true, print the current i value). (Line 5 - 9)

The most direct way to ensure all the prime numbers below 10000 are found, is to check the prime status from number 2 - 9999 which is amount to 9998 of numbers.

Next we create a second version of method to check prime, isPrime2 (Line 31 - 40). This version differs from the first version by only changing the for loop condition to i <= square root of n (Line 33).  In the main program, we create another for loop and  repeatedly call the second version of method (Line 13 - 17). We also get the same output as in the previous version.

8 0
3 years ago
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