I am assuming this is a true or false question? If so, the answer is true.
Answer:
It can be "ON" or "OFF". So it can store the numbers 1 and 0, but it certainly doesn't have the capacity to store a letter of the alphabet.
Explanation:
Answer:You can only find REaccuracy if you know the actual “true” measurement… something that's difficult to do unless you're measuring against the atomic clock. The formula is: REaccuracy = (Absolute error / “True” value) * 100%.
Explanation:
Please provide the language you're using when you ask for programming help, otherwise you aren't going to get the answer that you are looking for.
Here it is in Java, and I'm assuming the number is given via user input? Otherwise, just remove the user input function and replace the integer with a value of your choice. Note, that this isn't the full code; only what is relevant to the question.
public static void main(String[] args) {
int num = numInput(10);
printDoubles(num, 100); // You can create a user input function for
// maxValue if you wanted to.
}
/**
* Receives user input between 0 and the absolute value of maxInput.
* @param maxInput The largest absolute value that can be input.
*/
private static int numInput(int maxInput) {
Scanner sc = new Scanner(System.in);
maxInput = Math.abs(maxInput);
int num = 0;
while (!(num > 0 && num <= maxInput)) {
num = sc.nextInt();
if (!(num > 0 && num <= maxInput)) {
System.out.println("Input too small or too large");
}
}
return num;
}
/**
* Continues to print out num doubled until maxValue is reached.
* @param num The number to be printed.
* @param maxValue The maximum value (not including in which num can be doubled to.
*/
private static void printDoubles(int num, int maxValue) {
if (num >= maxValue) {
System.out.println("No output.");
}
while (true) {
if (num >= maxValue) {
break;
}
if (num < maxValue) {
System.out.print(num + " ");
}
num *= 2;
}
System.out.println();
}
