First one :
We divide it into two rectangles (the top one has dimensions 2in*4in)
The area of the top rectangle is 2*4=8 in^2
The second rectangle has dimensions 3*(5-3)=6 in^2
Hence the total area is 8+6=14 square inches
Second one :
We divide it into a rectangle (dimensions 11*17) and a triangle on the top.
The area of the rectangle is 11*17=187 m^2
The rectangle has dimensions 17 (base's length) and 23-11 (height) hence its area is 17*(23-11)/2=102 m^2
Hence the total area is 102+187=289 square meters
A. You would use base*height (bh). You would multiply 4 and 5. The answer is 20in.
B. It would be 1/3*bh. The answer would be 6.6.
Answer:
iba nalang
Step-by-step explanation:
just tell someting wag yan
C, E, and F have 50 50 chance
You can set up a systems of equations to solve this problem.
The equation y = 2x-3 represents the father's age where y = The father's age and x = The son's age.
The equation 30=y-x represents the difference between the two ages.
In order to be able to solve a system, the two equations can be in the same form. (They don't need to be it's just easier for me to have them in the same form) One is in standard form (ax+by= c) and the other one is in slope intercept form (y=mx+b where m is the slope and b is the y- intercept).
Lets put the equation y=2x-3 into standard form.
y=2x-3
+3 +3
y+3=2x
-y -y
3=2x-y
We have the two equations 30=y-x and 3=2x-y
Now to solve the system.
30=y-x
3=2x-y or 3=-y+2x
30=y-x
3=-y+2x The -y and y cancel each other out since they are the same term but are the inverse of each other one is neg one is pos.
Your left with
30=-x Now you just combine the two equations. 30+3 and 2x-x
3=2x
33=x The son's age is 33. To Find the Fathers age we would just plug 33 for x into one of the equations to find the Fathers age.
SON'S AGE IS 33
