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Marizza181 [45]
3 years ago
8

There are 1,861 students at Genoa Middle School. Each classroom can seat 33 students. How many classrooms are needed to seat all

the students?
Mathematics
1 answer:
Katen [24]3 years ago
7 0
1861/33= 56.4 but we round it up to the next whole number to fit all of the students so it is 57 classrooms
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Isabella invited some friends to her birthday party, but a few weren't able to attend. Of the friends she invited, 8 attended. T
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80% or like 8 squares out of 10 oe=r 4 out of 5 ect

Step-by-step explanation:

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Suppose you know the length of a confidence interval of a population mean is 8.4 and the sample mean (x bar) is 10. Find the ​ma
SOVA2 [1]

Answer:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

The lenght of the interval correspond to:

8.4 = 2ME

ME= \frac{8.4}{2}= 4.2

And since we know the margin of error we can find the limits for the confidence interval:

Lower = 10 -4.2=5.8

Upper = 10 +4.2=14.2

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X=10 represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Solution to the problem

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The sample mean \bar X is distributed on this way:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})  

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

The lenght of the interval correspond to:

8.4 = 2ME

ME= \frac{8.4}{2}= 4.2

And since we know the margin of error we can find the limits for the confidence interval:

Lower = 10 -4.2=5.8

Upper = 10 +4.2=14.2

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3 years ago
How to I solve this problem?
Arturiano [62]

Answer:

x=3

Step-by-step explanation:

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4 years ago
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Each child has 4 apples. If there are 39 children, how many apples are there in total
kodGreya [7K]

156Answer:

Step-by-step ex

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3 years ago
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Question
andrezito [222]

Answer:

56

Step-by-step explanation:

Arithmetic mean is simply the sum of the all the number present divide by the total number.

From the question, we obtained the following information:

The arithmetic mean = 5.6

Total number present = 10

Sum of the numbers =?

Arithmetic mean = sum of the numbers / total number

Sum of the numbers = arithmetic mean x total number

Sum of the numbers = 5.6 x 10 = 56

3 0
3 years ago
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