Hello! can you post the graph and the question? then i will certainly help you!
The greatest common factor of 96 and 5 is 1 and the greatest common factor of 64 and 27 is 1 as well. Hope this helped:)
Your answer would be <u>176.71</u>
hope this helps!
Answer:
The number of ways to select 5 diamonds and 3 clubs is 368,082.
Step-by-step explanation:
In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.
Compute the probability of selecting 5 diamonds and 3 clubs as follows:
The number of ways of selecting 0 cards from 13 hearts is:
![{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1](https://tex.z-dn.net/?f=%7B13%5Cchoose%200%7D%3D%5Cfrac%7B13%21%7D%7B0%21%5Ctimes%2813-0%29%21%7D%20%3D%5Cfrac%7B13%21%7D%7B13%21%7D%3D1)
The number of ways of selecting 3 cards from 13 clubs is:
![{13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286](https://tex.z-dn.net/?f=%7B13%5Cchoose%203%7D%3D%5Cfrac%7B13%21%7D%7B3%21%5Ctimes%2813-3%29%21%7D%20%3D%5Cfrac%7B13%21%7D%7B13%21%5Ctimes10%21%7D%3D286)
The number of ways of selecting 5 cards from 13 diamonds is:
![{13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287](https://tex.z-dn.net/?f=%7B13%5Cchoose%205%7D%3D%5Cfrac%7B13%21%7D%7B5%21%5Ctimes%2813-5%29%21%7D%20%3D%5Cfrac%7B13%21%7D%7B13%21%5Ctimes8%21%7D%3D1287)
The number of ways of selecting 0 cards from 13 spades is:
![{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1](https://tex.z-dn.net/?f=%7B13%5Cchoose%200%7D%3D%5Cfrac%7B13%21%7D%7B0%21%5Ctimes%2813-0%29%21%7D%20%3D%5Cfrac%7B13%21%7D%7B13%21%7D%3D1)
Compute the number of ways to select 5 diamonds and 3 clubs as:
![{13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082](https://tex.z-dn.net/?f=%7B13%5Cchoose0%7D%5Ctimes%7B13%5Cchoose3%7D%5Ctimes%7B13%5Cchoose5%7D%5Ctimes%7B13%5Cchoose0%7D%20%3D%201%5Ctimes286%5Ctimes1287%5Ctimes1%3D368082)
Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.