Y2-y1/x2-x1
(1,14) & (3,4)
y2= 4
y1=14
x2=3
x1=1
So....
(4-14)/(3-1) = -10/2 = -5
The answer should be negative instead of positive, she probably subtracted 4 from 14 instead.
Let ????C be the positively oriented square with vertices (0,0)(0,0), (2,0)(2,0), (2,2)(2,2), (0,2)(0,2). Use Green's Theorem to
bonufazy [111]
Answer:
-48
Step-by-step explanation:
Lets call L(x,y) = 10y²x, M(x,y) = 4x²y. Green's Theorem stays that the line integral over C can be calculed by computing the double integral over the inner square of Mx - Ly. In other words
Where Mx and Ly are the partial derivates of M and L with respect to the x variable and the y variable respectively. In other words, Mx is obtained from M by derivating over the variable x treating y as constant, and Ly is obtaining derivating L over y by treateing x as constant. Hence,
- M(x,y) = 4x²y
- Mx(x,y) = 8xy
- L(x,y) = 10y²x
- Ly(x,y) = 20xy
- Mx - Ly = -12xy
Therefore, the line integral can be computed as follows
Using the linearity of the integral and Barrow's Theorem we have
As a result, the value of the double integral is -48-
10:12. or 83.3%. so you have a 10 in 12 chance to not get a black one.
Y= a(x-3)^2+6
2= a(0-3)^2+6
2=a(-3)^2+6
2=a(9)+6
2-6=9a
-4=9a
-4/9=a
Therefore the equation in vertex form is
y = -4/9 (x-3)^2+6
Given the numbers on the computer 123 is shown very complicated. Well it’s not given all the numbers and mind thinking if u add formula 1 that shows that I have no idea what to tell you and ur stuck