If you are asking the place value it is thousand. if you are asking about it all it is, 7 thousand 8 hundred 54 and 2 hundred 9 thousanths.
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Answer:
He shpt 2 under par for both rounds 3 and 4
Step-by-step explanation:
-4 + 2 = -2
-8 - (-2) = -4
-4 / 2 = -2
Average rate of change over interval [a,b]: r=[f(b)-f(a)]/(b-a)
In this case the interval is [0,2], then a=0, b=2
r=[f(2)-f(0)]/(2-0)
r=[f(2)-f(0)]/2
1) First function: h(x)
r=[h(2)-h(0)]/2
x=2→h(2)=(2)^2+2(2)-6
h(2)=4+4-6
h(2)=2
x=0→h(0)=(0)^2+2(0)-6
h(0)=0+0-6
h(0)=-6
r=[h(2)-h(0)]/2
r=[2-(-6)]/2
r=(2+6)/2
r=(8)/2
r=4
2) Second function: f(x)
A function, f, has an
x-intercept at (2,0)→x=2, f(2)=0
and a y-intercept at (0,-10)→x=0, f(0)=-10
r=[f(2)-f(0)]/2
r=[0-(-10)]/2
r=(0+10)/2
r=(10)/2
r=5
3) Third function: g(x)
r=[g(2)-g(0)]/2
From the graph:
g(2)=6
g(0)=2
r=(6-2)/2
r=(4)/2
r=2
4) Fourth function: j(x)
r=[j(2)-j(0)]/2
From the table:
x=2→j(2)=-8
x=0→j(0)=4
r=(-8-4)/2
r=(-12)/2
r=-6
Answer:
Pairs
1) h(x) 4
2) f(x) 5
3) g(x) 2
4) j(x) -6
Answer:
4000 is size of a crowd walking in a charity fundraising March.
Step-by-step explanation:
Given:
Dimensions of rectangular space 10 feet by 12000 feet
So we can say that,
Length = 1200 ft
Width = 10 ft
Now we will calculate the area of rectangular space which is given by
Hence Area will be = 
Now we know that 40 people occupy a rectangle measuring 10 feet by 12 feet.
Length = 12 ft
Width = 10 ft
Area = 
It says that 40 people are occupied in 120 
So how many people will be there in 12000
By using unitary method we get,
Number of people = 
Size of a crowd walking in a charity fundraising March is 4000.
