<u>Answer:</u>
The basic identity used is
.
<u>Solution:
</u>
In this problem some of the basic trigonometric identities are used to prove the given expression.
Let’s first take the LHS:

Step one:
The sum of squares of Sine and Cosine is 1 which is:

On substituting the above identity in the given expression, we get,
Step two:
The reciprocal of cosine is secant which is:

On substituting the above identity in equation (1), we get,

Thus, RHS is obtained.
Using the identity
, the given expression is verified.
Answer:
4.5
Step-by-step explanation:
Answer:
-15 < 20
Step-by-step explanation:
5(w - 3) < 5w + 20
Distribute;
5w - 15 < 5w + 20
Subtract 5w from both sides;
-15 < 20
Answer:
7z + 5 + 6z - 9 (Add 7z and 6z, subtract 9 from 5)
<em>13z - 4 </em>(Can't be simplified further)
Hiii :))
Answer is in the attachment.
Identity used :-
1) cosec² α = 1 + cot² α
Trigonometric Ratio :-
1) cot 30° = √3
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