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2 years ago

Determine if it is a function, find the domain and the range.

Mathematics

1 answer:

wlad13 [49]2 years ago

6 0

Answer:

it is not function

Step-by-step explanation:

because,

first of all,what do mean function

A function is a relation in which each element of the domain corresponds to exactly one

element of the range.

based on this description

Since the domain element 1 is assigned to two different values in the range, -1 and 1, so that it is

not a function

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Find an equation for the nth term of the arithmetic sequence.

babymother [125]

Answer:

The common difference would be calculated as:

(a21-a19)/2

(-164--(-58 ))/2 (Replacing the values )

(-164 +58)/2 (Changing signs)

(-106)/2(Subtracting)

-53

Then we are going to replace the common difference(d) in the sequence formal with the 21st term . It is done for finding the first term of the sequence.

a21=a0+d*(n-1)

-164=a0+-53*(21-1) (Replacing the values)

-164=a1-53(20) (Subtracting)

-164=a1-1060 (Multiplying )

-164+1060=a1 (Adding 1060 on both sides of the equation)

896=a1

The answer would be : an= 896-53*(n-1), which is the option B.

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2 years ago

Find the solution of the given simultaneous equations<br> y = 2x - 3<br> 3x - 2y = 4

topjm [15]

Answer:

Step-by-step explanation:

x+3y=1

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1 year ago

Read 2 more answers

How do you write 4/ 9 as a decimal?

olasank [31]

Answer:

.4 repeating

Step-by-step explanation: divide the top number by the bottom number so 4 divided by 9

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2 years ago

The Sine Function

densk [106]

Answer:

C. Wave-like and repetitive

Step-by-step explanation:

I calculated it logically

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2 years ago

What are the possible values of x in 8x2 + 4x = -1?

Westkost [7]

Answer:

The possible values of x are:

x= $\frac{-1+\sqrt{3}}{4} \,\,or\,\, x= 0.18$

and

x= $\frac{-1-\sqrt{3}}{4} \,\, or \,\, x= -0.68$

Step-by-step explanation:

$8x^2+4x+1=0$

Using Quadratic formula to solve this equation:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a = 8 \,\, b = 4\,\, c = -1\\Putting \,\, values \,\, in \,\, the\,\, equation\\x= \frac{-4\pm\sqrt{(4)^2-4(8)(-1)}}{2(8)}\\x= \frac{-4\pm\sqrt{16+32}}{16}\\x= \frac{-4\pm\sqrt{48}}{16}\\x= \frac{-4+ \sqrt{48}}{16} \,\, and \,\, x= \frac{-4- \sqrt{48}}{16}\\x= \frac{-1+ \sqrt{3}}{4} \,\, and \,\, x= \frac{-1- \sqrt{3}}{4}$

The possible values of x are:

x= $\frac{-1+\sqrt{3}}{4} \,\,or\,\, x= 0.18$

and

x= $\frac{-1-\sqrt{3}}{4} \,\, or \,\, x= -0.68$

4 0

3 years ago