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2 years ago

Plz answer these 2 I’ll mark brainliest

Mathematics

2 answers:

adoni [48]2 years ago

8 0

Answer:

THE ANSWER

Step-by-step explanation:

MARK BRAINLIEST

vovikov84 [41]2 years ago

4 0

Answer:

16. C

17. B

sorry if i got it wrong

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The vertices of a right triangle are (0, 0), (1, 0), and (0, 1).

Alchen [17]

Answer:

(3,3)

Step-by-step explanation:

Given

$Vertices: (0,0)\ (1,0)\ (0,1)$

$Scale\ Factor = 3$

Required

Determine which can't be any of the new vertices

First, we need to determine the new vertices:

$New\ Vertex = Scale\ Factor * Old\ Vertex$

For (0,0):

$New\ Vertex = 3 * (0,0)$

$New\ Vertex = (3 * 0,3 * 0)$

$New\ Vertex = (0,0)$

For (1,0):

$New\ Vertex = 3 * (1,0)$

$New\ Vertex = (3 * 1,3 * 0)$

$New\ Vertex = (3,0)$

For (0,1):

$New\ Vertex = 3 * (0,1)$

$New\ Vertex = (3 * 0,3 * 1)$

$New\ Vertex = (0,3)$

Comparing the calculated new vertices to the list of given options; (3,3) can't be any of the new vertices of the new triangle

5 0

3 years ago

What is 2^4/3 equal to

In-s [12.5K]

16 squared root with 3

4 0

3 years ago

Read 2 more answers

This so fking confusing

love history [14]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

NEED HELP ASAP

Stels [109]

9, 12, 19, 30, ...

formula for the nth term is;

2n^2 + 3n - 10

6 0

2 years ago

How to solver for 2y-1/3=5 prove: y= 8

nirvana33 [79]

3×2y-(1/3×3)=5×3
6y-1=15
6y-1+1=15+1
6y=16
y=8/3
Y cannot be 8

3 0

3 years ago