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meriva
3 years ago
13

Plz answer these 2 I’ll mark brainliest

Mathematics
2 answers:
adoni [48]3 years ago
8 0

Answer:

THE ANSWER

A

B

Step-by-step explanation:

MARK BRAINLIEST

vovikov84 [41]3 years ago
4 0

Answer:

16. C

17. B

sorry if i got it wrong

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Estimate the sum of 487 and 310
Anika [276]
487 and 310 round to 800
8 0
3 years ago
Read 2 more answers
Find the area of a rectangle whose perimeter is 60in and width is 10in.
Dafna1 [17]

Answer:

250 sq. inch

Step-by-step explanation:

Perimeter: 60 inch

: 2 X L+B

: 2 X ? + 10

Length: 60-10

: 50/2

: 25 inch

Area: L X B

: 25 X 10

: 250 sq.inch

Hope it helps ;)

Please tell if it's correct

Please mark as brainliest!

3 0
2 years ago
A teacher's assistant entered 10 scores into the online gradebook in
-Dominant- [34]

Answer:

Ok I got it it’s 50

Step-by-step explanation:

because To divide by

1

5

, multiply by its reciprocal, 5.

10÷

1

5

= 105

= 50

8 0
3 years ago
Hi! I need help with this question for my Algebra 1 class:
MrMuchimi
Y + 1 = 5(x - 7)

y + 1 = 5x - 35

y = 5x - 36
8 0
3 years ago
The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

P(X>3417) =0.0166

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0
3 years ago
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